This question explores the difference between the integral • î dA over a closed Gaussian surface and the integral ·d i around a closed path. The electric field due to stationary charges (not shown) is measured at locations on a Gaussian box with dimensions L = 5 mm and h = w = 1.5 mm as shown below. The electric field on the surface of the right half of the box is uniform with magnitude 4 x 10° V/m. On the left half of the box E ~ 0. L/2 L/2 h Part 1 What is the total electric flux on the surface of the Gaussian box? i V-m Hint Assistance Used Save for Later Attempts: 0 of 10 used Submit Answer Part 2 What is the charge inside the box? 2 Tinside = C i Hint Save for Later Attempts: 0 of 10 used Submit Answer

This question explores the difference between the integral • î dA over a closed Gaussian surface and the integral ·d i around a closed path. The electric field due to stationary charges (not shown) is measured at locations on a Gaussian box with dimensions L = 5 mm and h = w = 1.5 mm as shown below. The electric field on the surface of the right half of the box is uniform with magnitude 4 x 10° V/m. On the left half of the box E ~ 0. L/2 L/2 h Part 1 What is the total electric flux on the surface of the Gaussian box? i V-m Hint Assistance Used Save for Later Attempts: 0 of 10 used Submit Answer Part 2 What is the charge inside the box? 2 Tinside = C i Hint Save for Later Attempts: 0 of 10 used Submit Answer

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter7: Electric Potential

Section: Chapter Questions

Problem 72P: The practical limit to all electric field in air is about 3.00106 N/C. Above this strength, sparking...

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