Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick, with a dielectric constant of K = 3.60. The I can't found part c resultant electric field in the dielectric is 1.20 × 106 volts per meter. Part A Compute the magnitude of the charge per unit area o on the conducting plate. Express your answer in coulombs per square meter to three significant figures. • View Available Hint(s) o = 3.82x10-5 C/m² Submit Previous Answers Correct Part B Compute the magnitude of the charge per unit area o1 on the surfaces of the dielectric. Express your answer using three significant figures. • View Available Hint(s) 01 = 2.76x10-5 C/m² Submit Previous Answers Correct Note that the charges on the dielectric will be polarized to counteract the charges (and electric field) created by the capacitor. For example, near the positive surface of the capacitor the dielectric will have a negative charge. However, this does not mean that the charge on the capacitor plates changes, only that the dielectric has an induced charge on each of its surfaces that will oppose the effects of the charges on the plates. Part C Find the total electric-field energy U stored in the capacitor.
Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick, with a dielectric constant of K = 3.60. The I can't found part c resultant electric field in the dielectric is 1.20 × 106 volts per meter. Part A Compute the magnitude of the charge per unit area o on the conducting plate. Express your answer in coulombs per square meter to three significant figures. • View Available Hint(s) o = 3.82x10-5 C/m² Submit Previous Answers Correct Part B Compute the magnitude of the charge per unit area o1 on the surfaces of the dielectric. Express your answer using three significant figures. • View Available Hint(s) 01 = 2.76x10-5 C/m² Submit Previous Answers Correct Note that the charges on the dielectric will be polarized to counteract the charges (and electric field) created by the capacitor. For example, near the positive surface of the capacitor the dielectric will have a negative charge. However, this does not mean that the charge on the capacitor plates changes, only that the dielectric has an induced charge on each of its surfaces that will oppose the effects of the charges on the plates. Part C Find the total electric-field energy U stored in the capacitor.
Chapter5: Electric Charges And Fields
Section: Chapter Questions
Problem 66P: On a typical clear day, the atmospheric electric field points downward and has a magnitude of...
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Transcribed Image Text:Two oppositely charged but otherwise identical
conducting plates of area 2.50 square centimeters
are separated by a dielectric 1.80 millimeters thick,
with a dielectric constant of K = 3.60. The
I can't found part c
resultant electric field in the dielectric is 1.20 x 10°
volts per meter.
Part A
Compute the magnitude of the charge per unit area o on the conducting plate.
Express your answer in coulombs per square meter to three significant figures.
• View Available Hint(s)
o = 3.82x10-5 C/m²
Submit
Previous Answers
Correct
Part B
Compute the magnitude of the charge per unit area o1 on the surfaces of the dielectric.
Express your answer using three significant figures.
• View Available Hint(s)
ơ1 = 2.76x10-5 C/m²
Submit
Previous Answers
Correct
Note that the charges on the dielectric will be polarized to counteract the charges
(and electric field) created by the capacitor. For example, near the positive surface of
the capacitor the dielectric will have a negative charge. However, this does not mean
that the charge on the capacitor plates changes, only that the dielectric has an
induced charge on each of its surfaces that will oppose the effects of the charges on
the plates.
Part C
Find the total electric-field energy U stored in the capacitor.
Express your answer in joules to three significant figures.
» View Available Hint(s)
?
U = 10.322
J
Submit
Previous Answers
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