The special case return value that will terminate the following code i
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The special case return value that will terminate the following code is ____________________.
int Sum(int n)
{
if(n < 2)
return 0;
else
return (n + Sum(n-1));
}
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- Java - Functions with 1D Arrays Create a program that asks the user for the size of an integer array and the elements of the array. Then, create a function called maxArray() with the following details: Parameters: An integer array The size of the integer array Return type - int Return value - the maximum value of the integer array Call the function you created in the main and pass the integer array and its size to it. Make sure to store the return value in a variable so you could print it afterwards. Input 1. First line contains the size of the array 2. Succeeding lines are the elements of an array 3. First line contains the size of the array 4. Succeeding lines are the elements of an array 5. First line contains the size of the array 6. Succeeding lines are the elements of an array 7. First line contains the size of the array 8. Succeeding lines are the elements of an array Output Enter size of array: 5 Enter element 1: 1 Enter element 2: 2 Enter…Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxThe special case return value that will terminate the following code is ____________________. int factorial(int n) { if(n <= 1) return 1; else return(n * factorial(n-1)); }
- int a[ 10] = {1,5,3,8,4,2,6,9,7}; int *p; p = &a[2]; p[0] = 10; p[1] = 15; What are the values of a? Select one: O a. {10,15,3,8,4,2,6,9,7} O b. {1,15,10,8,4,2,6,9,7} O c. {1,5,10,15,4,2,6,9,7} O d. {1,10,15,8,4,2,6,9,7}double tab1[5] = {2,3,4,5,6}; double tab2[5] = {6,5,4,3,2}; for(int i = 0;i<5;i++) { tab1[i] = tab1[i]*tab2[i]; cout<<tab1[i]<<" "; } 12 15 16 15 16 15 15 16 15 12 12 15 16 15 12 12 15 12 15 12function main() { # ist: input numbers #w: outer for loop index # X: inner for loop index # y: number of parsmeters # min: index for max value at the time of iteration # buf: used for swapping ____________________a _______ #declare local vars let=___________b___ #intialize aary with the parametrs y= _______c___ # find the lenght of lstfor((________________)); do min=________e_____ # intialize main index for ((___________f_______)); do # find index for main value in one line. use a short tets. _________g_____done # swap- two values using two indices, min and outerloop # use buf to hold value when swapping ________________h________ # move min lst [.] to buf ________________i_______ # move lst[.] to lst[.] _________________j_____ # move buf to lst[.]done}main "@" # pass the input parameters to the function main# end of bash script show me the ss when u run chatgpt doesnt give right code
- int FindSmallestVal() { int num = 0, min = 0; // reads num until the num > 0 while (num <= 0) { cin >> num; // finds the min value in the min,num min = num < min ? num : min; } // returns min return min; }#includecstdio.h> int x=10; void func1() 7 printf("x=%d\n", x); return; 8 10 int func2(int a, int b) 15 return a+b; 16 18 19 ... func3(...) 20 21 .. return ... int main() 27 { int x-1, y=2; func1(); 28 29 30 int z=func2(x, y); printf("z-%d\n", z); 31 34 Figure 2. C Program for Q2 What is the output after execution of line 29 and 32? a. b. func3() in line 19 to 23 is incomplete. Write the function, func30 to compute and print the volume of cuboid with length x, width y and height z. c. Complete line 33 to call func3() that you created in part (b).#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…
- #include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…