The outer radius of a coaxial cylindrical electrode system is given as 38 cm. The system is the most suitable sized according to puncture. Penetration of the insulator between the cylindrical layers Its strength is Ed = 78 kV / cm and the relative dielectric constant of the insulator is r1 = 40. a) - Calculate the capacity of the system and get the highest possible application without puncture to the system. Please respect what the voltage should be. b) - For the case of U = 180 kV application, the maximum and minimum occurrence on the system Calculate the electric field values? c) -Calculate the actual distance (d) of the system, the utilization factor (n) of the electrode aperture (alpha)? (Ɛ0 = 8,854x10-12 F / m)

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Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.