2. An infinitely long coaxial cable has an inner and an outer conductor of radii "a" and "b" respectively. If the space between the conductors is filled with two different dielectrics of dielectric costants E, and ez as shwon below, find the capacitance per unit length of this coaxial cable. (. "
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- A standard conductor having a radius of 1 cm. Find the inductance for strandard and hollow conductor both at a distance of 2.5 m and mention which one is higher.An infinitely long coaxial cable has an inner and an outer conductor of radii "a" and "b"respectively. If the space between the conductors is filled with two different dielectrics ofdielectric costants ɛ1 and ɛ2 as shwon below, find the capacitance per unit length of this coaxialcable1. Inductance. Consider the configuration of a wire with 90° bends as shown below. A small loop, with its sides of length a and width d = a/16 is placed with its plane lying along xz principal plane as shown. Stating all assumptions, determine mutual inductance between the loop and the wire. a/2 9/2 2a
- 2) C. When the capacitor is fully charged, the top conductor while the bottom conductor D. Electric field lines are and a potential difference is E. The capacitance of a capacitor is defined as F. The unit of capacitance is2. An infinitely long coaxial cable has an inner and an outer conductor of radii "a" and "b" respectively. If the space between the conductors is filled with two different dielectrics of dielectric costants ɛ1 and ɛ2 as shwon below, find the capacitance per unit length of this coaxial cable. EsDetermine the mutual inductance between a very long straightwire and a conducting circular loop of radius “b” m set up “d” mapart on the same plane as shown figure.Problem:
- A Suppose a copper conductor of length (UUm and cross-sectional area (A)m" and resistivity (6)N m, its resistance is [R = p(1/A)]. This copper conductor wounded around a ferromagnetic core, forming (N) turns. When this coil fed by a DC voltage (Va), its steady state current will be [lae = (Vac/R)]. But when this coil fed by an ms value of an AC voltage (Vms = Vdc), a steady state AC current of an rms value (lac) will pass through it. Explain the following questions: a) Why (lac < ldc) in this case, in spite of (Vms = Va)? What happens inside the electric circuit leads to reduce the current? b) What is the current waveform in this case? c) What is the voltage waveform across the coil? d) What is the type of the ammeter used in this circuit? e) Assume that the core length (le), cross sectional area (Ac), and its hysteresis loop data are known, what is its self inductance (L)? f) is the self inductance of this coil been constant? Or not? Why? g) If it is not constant, then what is it…A ferromagnetic core with a relative permeability of 1500 is shown in the given figure. The dimensions are as shown in the diagram, and the depth of the core is 5 cm. The air gaps on the left and right sides of the core are 0.050 and 0.070 cm, respectively. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A: (a) What are the flux values for the left, center and the right legs of the core? (b) What is the flux density in each air gap? 7 cm -30 cm- 7 em 30 ст 7 cm 30 cm -0.07 cm 300 turns 0.05 cm- 7 сm Core depth = 5 cmA ferromagnetic core with a relative permeability of 1500 is shown in the given figure. The dimensions are as shown in the diagram, and the depth of the core is 5 cm. The air gaps on the left and right sides of the core are 0.050 and 0.070 cm, respectively. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A: (a) What are the flux values for the left, center and the right legs of the core? (b) What is the flux density in each air gap? 30 cm- 30 cm 7 cm 30 cm 0.07 cm 300 turns 0.05 cm cm Core depth - 5 cm
- A ferromagnetic core with a relative permeability of 1500 is shown in the given figure. The dimensions are as shown in the diagram, and the depth of the core is 5 cm. The air gaps on the left and right sides of the core are 0.050 and 0.070 cm, respectively. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A: (a) What are the flux values for the left, center and the right legs of the core? (b) What is the flux density in each air gap? 7 cm 30 cm 30cm- 7 cm 30 cm 0.07 cm 300 turns 0.05 cm 7 cm Activate Windows Go to Settings to activate Windows. Core depth - 5 cm> Figure 1 shows a ferromagnetic core whose mean path length is 40 cm. There is a small gap of 0.05 cm in the structure of the otherwise whole core. The cross-sectional area of the core is 12cm?, the relative permeability of the core is 4000 and the coil of wire on the core has 400 turns. Assume that fringing in the air gap increases the effective cross-sectional area of the air gap by 5 percent. Given this information. Find the total reluctance of the flux path (iron plus air gap) and the current required to produce a flux density of 0.5 T in the air gap. N=400 0.05 cm A-12 cm - 40 cm Figure 1A ferromagnetic core with a relative permeability of 1500 is shown in the Figure. The dimensions are shown in the diagram, and the depth of the core is 5cm. The air gaps on the left and right sides of the core are 0.050 and 0.070 cm, respectively. Because of the fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A, what are the flux values for the left, center, and right legs of the core? What is the magnetic field in each air gap? |7 cm 7 cm 7 cm to 30 cm 30 cm 7 cm 30 cm 0.07 cm 300 turns 0.05 cm 7 cm Core depth = 5 cm