The area of a square gate is (12.69m) provided in oil tank is hinged at its top edge figure below. Determine the necessary vertical pull to be applied at the lower edge to open the gate (N). Gasoline surface Negative pressure (8250N/m2) 1.8m Gaseline (S-0.77 hinge gate Vertical pull F
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- AIR . P = 7 KPä." 1.5 m OIL HINGE SG = 0.82 A TA 3m The gate shown in the figure is hinged at A and rests on a smooth floor at B. The gate is a square in shape with 3m x 3m in dimension, while it is submerged in oil (SG = 0.82) as shown. The air above the oil surface is under a pressure of 7KP.. If the gate weighs 5 KN, determine the vertical force "T" required to open the gate. (Notes: Hydrostatic force "F" is always perpendicular to the plane surface. Also, the h is the pressure head located at the center of gravity of the object, which means, what will be the height of the oil if I am going to convert the pressure at the top into oil) (A) 178.52 KN B 184.60 KN c) 202.66 KN (D) 196.36 KN (E) No answer among the choices GATE 3mNote: Please state what formula you are using. And please be clear and detailed with your solution. Atleast explain. It will help me, thanks. Problem: A Triangular gate having a horizontal base of 1.30 m and an altitude of 2 m is inclined 45o from the vertical with vertex pointing upward. The base of the gate is 2.70 m below the surface of oil (s = 0.80). What normal force must be applied at the vertex of the gate to open it? Show figureTwo vessel are connected to differential manometer using tubing being filled with water. The higher pressure vessel is than the other. (a) If the mercury reading is 110 in meters of water? (b) If carbon tetrachloride (s = iwould be the manometer reading for the same pressure difference ? mercury density = 13.6 Solution mercury, the connecting 1.38 m lower in elevation mm, what is the pressure head difference 1.59 )were use instead of mercury, what Air 4 water 3 m X Fig A 1.38 1 Air water gage liquid
- The area of a square gate is (12.69m) provided in oil tank is hinged at its top edge figure below. Determine the necessary vertical pull to be applied at the lower edge to open the gate (N). Gasoline surface Negative pressure (8250N/m2) 1.8m Gaseline (S-0.77 hinge gate Vertical pull F 145°5. For the setup shown in the figure, what is the pressure pA if the specific gravity of the oil is 0.82? (S.G. of Hg 13.6) Air Oil Орen 4 m H,0 320 mm Hg- Figure for Prob. No. 5There is a circular gate at the end of the tank as illustrated. A 6.387 * 10–3 m³ wood block is tied to the end of the gate as illustrated. Density of the wood block is 0.6 g/cm³. Water is at 15.6 °C and Mercury is at 20 °C. What will be the reading h approximately on the mercury manometer on the left side when the gate opens up? Water 50 Wood Hinge 0.4 m Gate D=4 cm Mercury O a. 0.1 m O b.0.14 m c. 0.22 m d. 0.26 m
- Please be clear with your solution. Make an explanation for the formula and solution you used. Problem: A Triangular gate having a horizontal base of 1 30 m and an altitude of 2 m is inclined 45 o from the vertical with vertex pointing upward The base of the gate is 2 70 m below the surface of oil s 0 80 What normal force must be applied at the vertex of the gate to open it? Show figurePlease be xlear and detailed with your answer. Write an explanation in every formula and solution you used. Problem: A Triangular gate having a horizontal base of 1 30 m and an altitude of 2 m is inclined 45 o from the vertical with vertex pointing upward The base of the gate is 2 70 m below the surface of oil s 0 80 What normal force must be applied at the vertex of the gate to open it? Show figureAn inclined rectangular gate with water on one side is shown in the figure. The gate has dimensions of 4 ft long and 5 ft wide. Detennine the hydrostatic force acting on the gate. Take e- 55 sf hece hep L. 9083.5 lb 11410.4 Ib 14100.3 Ib 12028.6 Ib 14763.8 Ib 13865.1 Ib 11102.7 Ib 13312.4 Ib 15081.2 Ib 12752.9 Ib 10761.8 Ib 10200.1 Ib O
- AIR : P= 7 KPä. 1.5 m OIL HINGE SG = 0.82 3m 2450 クの The gate shown in the figure is hinged at A and rests on a smooth floor at B. The gate is a square in shape with 3m x 3m in dimension, while it is submerged in oil (SG = 0.82) as shown. The air above the oil surface is under a pressure of 7KPa. If the gate weighs 5 KN, determine the vertical force "T" required to open the gate. (Notes: Hydrostatic force "F" is always perpendicular to the plane surface. Also, the h is the pressure head located at the center of gravity of the object, which means, what will be the height of the oil if I am going to convert the pressure at the top into oil) A 178.52 KN 184.60 KN 202.66 KN 196.36 KN No answer among the choices GATE 3mAn a tank filled with mercury (density 13000 kg/m3)at depth 10 m , the force actining at the hatch with diameter 0.75 m (located at the bottom tank) is (Taken gravitational acceleration as 10 m/s2):A tank is filled with fluid under prcssurc anti the prcssurc gauge fixcd at the top indicatcs a prcssurc of 21 kPa. The curved surfacc of the top is quarter of a circular part of radius 2.6 m. calculate the magnitude (N) and direction (degree) of the resultant force on the cun'ed surface. (p=950kg./m³for fluid)