This is the answerplz write clear handwritten plzzThe angular velocity vectorAB 6=w = wTa¯- 1.5₁² + 2ĵ+ k²(1.52 +2².(AB)+1²) 1/²-3.3421 +4.4561 +2.228 k had/sSimilarly angular aceleration2AB173111.11 - 14.81 - 7.42 k rad/5²= xVelocity of the point c.-->v₁ =W X BCX[-3.3421+4.456+2₁228k² ] × [1.5j]=-3.3421-5,013 K²=The aneleration of point C-72 x BC +=ас3x (2²+ BC)centripetalAangential= -11.2 ₁² - 24.21 +31.6 k m/s²

Given Data The angular velocity is:ω=6 rad/s The angular acceleration is:α=-25 rad/s2 To find: The…

Answered: The angular velocity vector AB -1.5 î+…

The angular velocity vector AB -1.5 î+ 2₁+ k² a. = W 6 [ (AB) (1.52 +2²+1²) 1/2 -3.3421 +4.4561¹ + 2.228 k had/s = Similarly angular aceleration = x AB 1731 11.11 14.81-7.42 ½ rad/s² - ४

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

This is the answer
plz write clear hand
written plzz
The angular velocity vector
AB 6
=
w = w
Ta
¯- 1.5₁² + 2ĵ+ k²
(1.52 +2².
(AB)
+1²) 1/²
-3.3421 +4.4561 +2.228 k had/s
Similarly angular aceleration
2
AB
1731
11.11 - 14.81 - 7.42 k rad/5²
= x
Velocity of the point c.
-->
v₁ =
W X BC
X
[-3.3421+4.456+2₁228k² ] × [1.5j]
=
-3.3421-5,013 K²
=
The aneleration of point C
-7
2 x BC +
=
ас
3x (2²+ BC)
centripetal
Aangential
= -11.2 ₁² - 24.21 +31.6 k m/s²

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