Suppose the alloy in Example 9.3 in your book is reprocessed to a temperature at which the liquid concentrate is 45 wt% B and the solid-solution composition is 85 wt% B. Calculate the amount of each phase.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question
100%

I think I am just overthinking this but can someone double-check me and correct me?

Suppose the alloy in Example 9.3 in your book is reprocessed to a temperature at which the liquid concentrate is 45 wt% B and the solid-solution composition is 85 wt% B. Calculate the amount of each phase.

 

EXAMPLE 9.3
The temperature of 1 kg of the alloy shown in Figure 9.30 is lowered
slowly until the liquid-solution composition is 18 wt % B and the solid-
solution composition is 66 wt % B. Calculate the amount of each phase.
SOLUTION
Using Equations 9.9 and 9.10, we obtain
Xss - x
66
50
(1 kg)
XL
(1 kg)
18
ML
Xss
66
0.333 kg
333 g
and
х — XL
50
18
(1 kg)
XL
(1 kg)
18
Mss
Xss
66
= 0.667 kg = 667 g.
Note. We can also calculate mss more swiftly by simply noting that
1,000 g
- m = (1,000 – 333) g = 667 g. However, we shall
Mss =
continue to use both Equations 9.9 and 9.10 in the example problems
in this chapter for the sake of practice and as a cross-check.
Temperature
FIGURE 9.30 A more quantitative
treatment of the tie line introduced in
Figure 9.6 allows the amount of each
phase (L and SS) to be calculated by
means of a mass balance (Equations 9.6
and 9.7).
L+ SS
T1
SS
30
50
80
100
A
Composition (wt % B)
В
ML +mss=Mtotal
0.30 mL +0.80 mss = 0.50 mtotal
→mL=0.60 mtotal
mss = 0.40 mtotal
Transcribed Image Text:EXAMPLE 9.3 The temperature of 1 kg of the alloy shown in Figure 9.30 is lowered slowly until the liquid-solution composition is 18 wt % B and the solid- solution composition is 66 wt % B. Calculate the amount of each phase. SOLUTION Using Equations 9.9 and 9.10, we obtain Xss - x 66 50 (1 kg) XL (1 kg) 18 ML Xss 66 0.333 kg 333 g and х — XL 50 18 (1 kg) XL (1 kg) 18 Mss Xss 66 = 0.667 kg = 667 g. Note. We can also calculate mss more swiftly by simply noting that 1,000 g - m = (1,000 – 333) g = 667 g. However, we shall Mss = continue to use both Equations 9.9 and 9.10 in the example problems in this chapter for the sake of practice and as a cross-check. Temperature FIGURE 9.30 A more quantitative treatment of the tie line introduced in Figure 9.6 allows the amount of each phase (L and SS) to be calculated by means of a mass balance (Equations 9.6 and 9.7). L+ SS T1 SS 30 50 80 100 A Composition (wt % B) В ML +mss=Mtotal 0.30 mL +0.80 mss = 0.50 mtotal →mL=0.60 mtotal mss = 0.40 mtotal
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Ceramics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY