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Step 1: C6HsCIN¿O2(aq) + NaNO2(aq) + 2HCI(aq) → C6H3CIN3O2*(aq) + Cl'(aq) + 2H2O(I) + NaCI(aq) =-1212 kJ/mol ΔΗ1 Step 2: C6H3CIN3O2*(aq) + Cl'(aq) + C10H10CINO2(aq) → C16H12CI2N4O4(aq) + HCl(aq) AH2 = 637 kJ/mol Overall Reaction: C6HsCIN2O2(aq) + NaNO2(aq) + HCI(aq) → 2H2O(1) + NaCl(aq) + C16H12CI2N4O4(aq) AHrxn = ? kJ/mol

Step 1: C6HsCIN¿O2(aq) + NaNO2(aq) + 2HCI(aq) → C6H3CIN3O2*(aq) + Cl'(aq) + 2H2O(I) + NaCI(aq) =-1212 kJ/mol ΔΗ1 Step 2: C6H3CIN3O2*(aq) + Cl'(aq) + C10H10CINO2(aq) → C16H12CI2N4O4(aq) + HCl(aq) AH2 = 637 kJ/mol Overall Reaction: C6HsCIN2O2(aq) + NaNO2(aq) + HCI(aq) → 2H2O(1) + NaCl(aq) + C16H12CI2N4O4(aq) AHrxn = ? kJ/mol

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.98QP
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The synthesis of Hansa yellow dye takes place in a series of two steps. On Sunday June 9th, 1996 a violent runaway reaction occurred causing very significant damage to equipment and buildings. After a detailed analysis, the plant was rebuilt, and production resumed. What is the enthalpy of the overall reaction? Show work for credit. Can you explain which of the two steps was most likely to blame for the incident? Step 1: CsH;CIN2O2(aq) + NANO2(aq) + 2HCI(aq) → C6H3CIN3O2*(aq) + Cl(aq) + 2H2O(I) + NaCI(aq) AH1 = -1212 kJ/mol Step 2: C6H3CIN3O2*(aq) + Cl'(aq) + C10H10CINO2(aq) → C16H12C12N4O4(aq) + HCl(aq) AH2 = 637 kJ/mol %3| Overall Reaction: C6H5CIN2O2(aq) + NaNO2(aq) + HCI(aq) → 2H2O(1) + NaCI(aq) + C16H12CI2N4O4(aq) AHrxn = ? kJ/mol %3D
Transcribed Image Text:The synthesis of Hansa yellow dye takes place in a series of two steps. On Sunday June 9th, 1996 a violent runaway reaction occurred causing very significant damage to equipment and buildings. After a detailed analysis, the plant was rebuilt, and production resumed. What is the enthalpy of the overall reaction? Show work for credit. Can you explain which of the two steps was most likely to blame for the incident? Step 1: CsH;CIN2O2(aq) + NANO2(aq) + 2HCI(aq) → C6H3CIN3O2*(aq) + Cl(aq) + 2H2O(I) + NaCI(aq) AH1 = -1212 kJ/mol Step 2: C6H3CIN3O2*(aq) + Cl'(aq) + C10H10CINO2(aq) → C16H12C12N4O4(aq) + HCl(aq) AH2 = 637 kJ/mol %3| Overall Reaction: C6H5CIN2O2(aq) + NaNO2(aq) + HCI(aq) → 2H2O(1) + NaCI(aq) + C16H12CI2N4O4(aq) AHrxn = ? kJ/mol %3D
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