3. Calculate the standard enthalphy of acetylene (CH2) form its elements: CH2) 2C(graphite)+ H2() The equations for each step are as follows: C(graphite) + O2(8) H2e) + 2C2H+ 502(8) CO2() AH = -393.5 kJ AH=-285.8 kJ %3D %3D 2 4CO2+ 2HO) AH=-2598.8 kJ %3D 4. The standard enthalpy of formation of hexane can be determined indirectly. Calculate the standard enthalpy of formation of hexane using the enthalpies of combustion (in kJ/mol) given just below. 19 CH14(0) + 6CO) + 7H;Ou) AH = -4163.0 kJ -> 2 Ceruphite) + Oz(g) CO2(e) AH = -393.5 kJ > H2) +O2e) AH = -285.8 kJ ->
3. Calculate the standard enthalphy of acetylene (CH2) form its elements: CH2) 2C(graphite)+ H2() The equations for each step are as follows: C(graphite) + O2(8) H2e) + 2C2H+ 502(8) CO2() AH = -393.5 kJ AH=-285.8 kJ %3D %3D 2 4CO2+ 2HO) AH=-2598.8 kJ %3D 4. The standard enthalpy of formation of hexane can be determined indirectly. Calculate the standard enthalpy of formation of hexane using the enthalpies of combustion (in kJ/mol) given just below. 19 CH14(0) + 6CO) + 7H;Ou) AH = -4163.0 kJ -> 2 Ceruphite) + Oz(g) CO2(e) AH = -393.5 kJ > H2) +O2e) AH = -285.8 kJ ->
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.52QE
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Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
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Transcribed Image Text:CH() + 202e)
Ceraphite) +O2(g) CO2()
2H2+O2e)
AH=-393.5 kJ
AH--571.6 kJ
AH=-890.4 kJ
2H2O)
->
CO) + 2H;Ou)
3. Calculate the standard enthalphy of acetylene (C2H2) form its elements:
C:H)
2C(graphite)+
+H2(s)
The equations for each step are as follows:
C(graphite) + O2(8)
Hue) + Oe
2C2He + 5O2e)
CO2(s)
AH =-393.5 kJ
AH=-285.8 kJ
2.
4CO2) + 2HOu)
AH=-2598.8 kJ
4. The standard enthalpy of formation of hexane can be determined indirectly. Calculate the
standard enthalpy of formation of hexane using the enthalpies of combustion (in kJ/mol)
given just below.
19
AH=-4163.0 kJ
CH140
6CO2) + 7H;Ou)
+
2.
AH =-393.5 kJ
%3D
CO2e)
Ceraphite) + O2(g)
H2ie +O2e)
AH =-285.8 kJ
H2Oay
Transcribed Image Text:Date:
Year & Section:
Exercise 1:
Problem Solving:
Solve the following problems with complete solution
1. Carbon occurs in two forms: graphite and diamond. Given the equation:
CO2(e)
CO2(e)
Calculate the AH for the conversion of graphite to diamond:
AH=-393.5 kJ
C(eraphite) + Ozig)
C(diamond) + Ozg)
%3D
AH3-395.4 kJ
->
C(graphite)
C(diamond)
2. Calculate for the change in enthalpy of:
C(eraphite) + 2H22)
Given the following information:
Cigraphite) + O2(e)
2HM) + O2(g)
CHe) + 202e)
CH(e)
AH=-393.5 kJ
CO2(e)
2H;O)
AH=-571.6 kJ
AH = -890.4 kJ
CO2e) + 2H2Ou)
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