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Solve the Energy Balance for Tad AH = AH+ (70.0 mol)Ĥ₂ + (30.0 mol)Ĥ3 + (30.0 mol)Ĥ4 – (100.0 mol)Ĥ₁ = 0 || Substitute for (= 30.0), AH;(= 69.11 kJ), Â₁(= 33.79 kJ/mol), and Ĥ₂ through Â4 AH = 5.190 × 10-¹0T+2.813 x 10-6T³ +7.492 × 10-³7²d+6.673Tad – 1477 = 0 This equation can be solved using an equation-solving program or a spreadsheet. The solution is

Solve the Energy Balance for Tad AH = AH+ (70.0 mol)Ĥ₂ + (30.0 mol)Ĥ3 + (30.0 mol)Ĥ4 – (100.0 mol)Ĥ₁ = 0 || Substitute for (= 30.0), AH;(= 69.11 kJ), Â₁(= 33.79 kJ/mol), and Ĥ₂ through Â4 AH = 5.190 × 10-¹0T+2.813 x 10-6T³ +7.492 × 10-³7²d+6.673Tad – 1477 = 0 This equation can be solved using an equation-solving program or a spreadsheet. The solution is

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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This is a reactive energy balance.  How do you calculate T?  

E Sign in O 136°F Clear A PDF Elementary Principles of Chemica X + Ⓒ File | E:/Elementary%20Principles%20of%20Chemical%20Processes,%204th%20Edition%20(%20PDFDrive%20).pdf Draw Read aloud Ask Copilot Solve the Energy Balance for Tad 532 of 695 I ad Search au = AH = AH + (70.0 mol)Ĥ₂ + (30.0 mol)Â3 + (30.0 mol)Ĥ4 — (100.0 mol)Â₁ = 0 || Substitute for ₹(= 30.0), AH; (= 69.11 kJ), ¦(= 33.79 kJ/mol), and Ĥ₂ through Â4 AH = 5.190 × 10-¹0T+2.813 × 10¯67³ +7.492 × 10-³T² +6.673T ad 1477 = 0 This equation can be solved using an equation-solving program or a spreadsheet. The solution is ad ad ad ☆ 185°G {} 39 8 P B. E. Poling, J. M. Prausnitz, and J. P. O'Connell, The Properties of Gases and Liquids, 5th Edition, McGraw-Hill, New York, 2001. The formula given has been derived from the one shown in this reference, which is for the heat capacity in J/(mol K) with the temperature expressed in kelvin. {" To obtain the solution using a spreadsheet, put a guessed value of Tad in one cell and the expression for AH in an adjacent cell, and use the Goal Seek tool to determine the value of Tad for which the expression for AH equals zero. A first guess might be the value of Tad obtained by dropping all higher-order terms in the expression, leaving 6.673Tad 1134 = 0 Tad ≈ 170°C. ENG Ⓡ 0 ⠀ X Edit with Acrobat 10:50 PM 2/4/2024
Transcribed Image Text:E Sign in O 136°F Clear A PDF Elementary Principles of Chemica X + Ⓒ File | E:/Elementary%20Principles%20of%20Chemical%20Processes,%204th%20Edition%20(%20PDFDrive%20).pdf Draw Read aloud Ask Copilot Solve the Energy Balance for Tad 532 of 695 I ad Search au = AH = AH + (70.0 mol)Ĥ₂ + (30.0 mol)Â3 + (30.0 mol)Ĥ4 — (100.0 mol)Â₁ = 0 || Substitute for ₹(= 30.0), AH; (= 69.11 kJ), ¦(= 33.79 kJ/mol), and Ĥ₂ through Â4 AH = 5.190 × 10-¹0T+2.813 × 10¯67³ +7.492 × 10-³T² +6.673T ad 1477 = 0 This equation can be solved using an equation-solving program or a spreadsheet. The solution is ad ad ad ☆ 185°G {} 39 8 P B. E. Poling, J. M. Prausnitz, and J. P. O'Connell, The Properties of Gases and Liquids, 5th Edition, McGraw-Hill, New York, 2001. The formula given has been derived from the one shown in this reference, which is for the heat capacity in J/(mol K) with the temperature expressed in kelvin. {" To obtain the solution using a spreadsheet, put a guessed value of Tad in one cell and the expression for AH in an adjacent cell, and use the Goal Seek tool to determine the value of Tad for which the expression for AH equals zero. A first guess might be the value of Tad obtained by dropping all higher-order terms in the expression, leaving 6.673Tad 1134 = 0 Tad ≈ 170°C. ENG Ⓡ 0 ⠀ X Edit with Acrobat 10:50 PM 2/4/2024
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