Solve for the Thevenin equivalent voltage (in Volts) of the network shown. Let V-30V and R=12 ohms. (Use 2 decimal places. Unit is not required.) V R I₁ V₁ [T]= 5 [0.4 S 102] 1 + V₂ 10 92
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- What is the difference between the cut-off voltage VGS0 f and the narrowing voltage Vp? Explain this with the diagramsolve using thevenins theorem(draw the step by step changes in the circuit diagram)solve the computed values1. RTH (measured values from tinkercad=56.8 ohms)2. VTH (measured values from tinkercad=2.27 V)3. I (measured values from tinkercad=0.04 A)The diagram in the figure shows a simple circuit consisting of a battery and a load consisting of two resistors.The battery voltage is UB = 56 V and the value of the resistors is:R1 = 1800R2 = 5400a) The ammeters in the circuit show the following value:A1 shows valueA2 shows valueA3 shows valueb) In the load, the effect developsc) The total resistance of the load is
- The currents i and it in the circuit in the figure are 8.0 A and - 4.0 A, respectively. Vis 200 V. (Figure 1) Figure Part A Submit Part B Find ig Express your answer with the appropriate units. Value Va Request Answer 392 P⁹ P10 P30. P16 . Pii n. ps . P4. P15 = 502 m Units Find the power dissipated in each resistor. Enter your answers separated by commas. 15 02 m for Part A for Part Indo for Part redo for Part A reset for Part A keyboard shortcuts for Part A help for Part A 1102 ww TZ vec X for Part B for Part B for Part B for Part B 30 Ω ww 16 02 w 100 40 1 of 1 Vndo for Parts redo for Part B reset for Part B keyboard shortcuts for Part B help for Part B WSolve for Ib and Ic. ... 4 RC RB 10002 50k2 VCC 25V 100A/A R3 Re 5k2 8002 Ib=Blank 1HA Ic=Blank 2 mA 5.Find Is and I1 to I3. For LED1 assume a voltage drop of 1.8V
- R2 Q1 ... VCC R1 Show your complete solution. Use two decimal places for your final answer. Calculate the value of RC in ohms. at VCC=18 V, IB=26 uA, and VC=7V and B=69How do I find the total Ohm's of this in steps? been on it forever now.*Explain how the conversion works here*The amount of current following in a circuit was measured to be I = 0.00037 A.a. Express in Powers of Ten for 10-1 , 10-2, 10-3, 10-4, 10-5, 10-60.0037 x 10-1A, 0.037 x 10-2A, etc.……b. Express in mA (milliamps or 10-3)c. Express in µA (micro amps or 10-6)