se 5-Bit RC4 to decrypt the message XNV@H -Translate between characters and numbers using ASCII minus 64 (so @=0, A=1,... _=31). -The key is DISCRETE.
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Use 5-Bit RC4 to decrypt the message XNV@H
-Translate between characters and numbers using ASCII minus 64 (so @=0, A=1,... _=31).
-The key is DISCRETE.
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- Computer Science -Use 5-Bit RC4 to decrypt the message XNV@H -Translate between characters and numbers using ASCII minus 64 (so @=0, A=1,... _=31). -The key is DISCRETE.Performing the bitwise XOR operation on A = 000111 and B = 001101 and enter the result. The result must also have a size of 6 bit. Use only "0" and "1" without any other characters or spaces. Do not add a prefix.a. Decode the encoded message by using the key matrix [1222] 27 28 48 56 9. 18 38 38 33 54 28 28 (Note: Use 0 for space AND start numbering the alphabets from 1 to 26 starting with A)
- 1. Generate the Hamming-code for the following 12-bit data string : 1 0 1 0 1 1 0 1 1 1 0 1 Show that the generated binary string does not have any errors.2. , A string encoded with H(12,8) SECDED is received as 0x500 Is it in error? Which bits are in error? extract the original message, show your work Bit position 1 2 3 4 5 6 7 8 9 10 11 12 Encoded date bits p1 p2 d1 p4 d2 d3 d4 p8 d5d6d7d8 X X X X X Parity X X X X X X bit coverate X X X X X X X X received Ox500 4 5 6 9 10 11 12 d1 p4 d2 d3 d5 d6 d7 d8 1 0 0 0 0 0 0 value should be 0 1 1 0 bit in error = bit position received message corrected original message p1 X p2 p4 p8 1 2 p1 p2 0 1 0 p1 p2 p4 p8 X X 7 8 d4 p8 0 0 in error? hex value 0x500An 8-bit byte with binary value 10101111 is to be encoded using an even-parity Hamming code. What is the binary value after encoding? ANS: The encoded value is 101001001111 Why is this answer longer from binary value? Please solve this question with details. Please explain why you use that method.
- Using an 8-bit floating-point format in which the most significant bit is the sign bit, the next three bits represent the exponent field in excess notation, and the last four bits represent the mantissa, write the bit pattern that represents the value 1 3/4. (Use normalized form.)In the steps of “Append the padding bits” in SHA-512 system (shown in Figure 1), the message is padded so that its length is congruent to 896 mod 1024 or (length ≅ 896 mod 1024). State the value of the following padding field is the message length is: a) 1919 b) 1920 c) 2942Convert 0100111011011110 16 bit real number to decimal? (Sign:1-bit Exp:5-bit Mant:10-bit excess-15)(Answer as mixed, reduced numeral with a single space seperating the whole number and the fraction. Ex. 14 1/4)
- The number -82 is represented as an integer with respect to the complement of 2 in 32 bits. According to this, a) If we rotate this number 8 bits to the left, what will be the result, show it in hexadecimal format? b) If we rotate this number 4 bits to the right, what will be the result, show it in hexadecimal format?For the ASCII string “MTU 1885”, calculate the 2D parity, using even parity throughout. Consult an ASCII table like www.asciitable.com, use 7-bit ASCII codes, and note that the string has 8 characters, including the space.Please do not give solution in image format thanku Present in UTF-8 the 32-bit code given below (in the solution, the byte order from MSB on the left): 11111111 11111111 10110110 11011011 In the solution, separate bytes with a space. If impossible - enter -1