QUESTION 3Linkage disequilibrium is defined by which of the following?O Positions in the genome where people vary by a single nucleotide baseO The occurrence of two alleles in the repulsion configurationO The probability that two genes are linkedO Crossing over that occurs between two genes that are located close to each otherO The nonrandom association between alleles in a haplotypeQUESTION 4Red-green color blindness is a human recessive X-linked disorder. A young man with a 47, XXY karyotype(Klinefelter syndrome) is colorblind. His mother and father have normal color vision, but his mother has a father whois colorblindDid the nondisjunction event that gave rise to the young man with Klinefelter syndrome happen in the mother, thefather or is it impossible to tell (assume that no crossing over took place in prophase I of meiosis)?a. Motherb. Fatherc. Impossible to tellDid this nondisjunction happen during Meiosis I, Meiosis II, or is it impossible to tell?a. Meiosis Ib. Meiosis IIc. Impossible to tell

For QUESTION 3:The correct answer is: The nonrandom association between alleles in a…

Answered: QUESTION 3 Linkage disequilibrium is…

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter11: Genome Alterations: Mutation And Epigenetics

Section: Chapter Questions

Problem 7QP

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Similar questions

Which of the following terms means many genes? polymorphism polygeny polypeptide multiple alleles
Klinefelter syndrome (XXY) can most be easily diagnosed by _______. a. pedigree analysis. b. aneuploidy c. karyotyping d. phenotypic treatment
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
QUESTION 2 Variable expression of the MERRF syndrome arises from recombination between nuclear and mtDNA O homoplasmic cells mitotic segregation nuclear genes environmental factors
Question 1 During nucleic acid hybridization, the probe is labelled for DNA stability to increase probe-test DNA binding to identify the location of probe and the test DNA binding for amplification Question 2 10 IV 8 10 11 12 13 14 Which of the following best describes the trait in the pedigree? Question 2 options: X-linked dominant X-linked recessive autosomal domiant autosomal recessive
oibai) s moil to to bludy 2019mnes or to in aldiz 212019m nool botibni arrow 100 muzes, nisgn esqyjonsg or to oily r R RE Parent 1 Question 5. In a related species of dragons, the fire breathy and flying loci are present on the same chromosome. Non-dividing diploid cells from two dragons are shown above. 22019 is most flest tedi non si to od to be in baribong A. What is the genotype of parent 1? (Use chromosomal notation if appropriate) non mowied OF Rr/11 B. What is the genotype of parent 2? (Use chromosomal notation if appropriate) L Rr/L LI C. Draw the what a cell from parent 2 would like in PROPHASE of MEIOSIS I. For the purpose of this question, ASSUME NO CROSSOVER between the fire breathing and flying loci. Make sure you label alleles on each DNA molecule. xRixr Parent 2 D. Draw what the two daugher cells would look like after the cell you drew in (C) has undergone meiosis I (the cells are ready to undergo meiosis II; assume no crossover between the indicated loci in meiosis I).…
Question 6 Which of the Pedigree Diagrams below is most likely to show a family with Becker muscular dystrophy? B Afected female Normal fenale anecad sale Nermal maie KEY Homozygous Homazygous Heterozygous Heberozygous Wild Type Male Fumale Male Female Male Female Note: Completely red symbol denotes an individual exhibiting the phenotype of interest C OT 12 12 12 IV 1/4 14 Alfected 12. 1/2 Known camer A A B. A, 8.
Calibri 12 - BIU A Section 4: Monohybrid test cross A monohybrid cross is a mating where alleles of just one gene are tracked in the offspring. A test cross is a mating in which two parents (P generation) are crossed to give F1 (first filial generation) offspring, and then two F1 parents are crossed to give F2 (second filial generation) offspring. By tracking offspring through two generations, a test cross can reveal patterns of inheritance for particular genes. 9. In a cross between a black and a white guinea pig, all members of the F1 generation are black. The F2 generation is made of % black and % white guinea pigs. Diagram this cross, and list the genotypes and phenotypes for each generation.
Question 1 What are the haploid genotypes of the gametes and frequencies/proportions of those gametes that can be formed in individuals of each of the following diploid genotypes? (DON’T do a cross. Just predict the different haploid gamete genotypes that could be produced by each diploid genotype below.) Proportions can be expressed in ratio form or fractional form. Dd Ee ff GG Mm Nn Rr ZZ
Question 38 Which of the following are associated with dynamic mutations? Genomic imprinting O Trinucleotide repeat diseases O Maternal effect diseases O Mitochondrial diseases O X-chromosome inactivation

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