Question 2This system below is a model of a custom electric heating system:R₁120 VLwwwwR3R4R₂Bu1. Determine the voltage across each resistor (heating element).busR₁ = 60R₂ = 40R3 = 100R4 = 120M0221 2. Determine the current flowing through each element.(Werstmalts3. Find the power dissipated by each element and the total power dissipated by the heating system.4. Determine the total power delivered by the voltage source using P=VI.Related equationsV = IRV²P = VI = I²R:R*Indicate all assumed voltage polarities and current directions

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Question 2 This system below is a model of a custom electric heating system: R₁- 120 V R2 1. Determine the voltage across each resistor (heating element). R4 www www R34 R₁ = 60 R₂ = 40 R3 = 100 R4 = 120

Question 2 This system below is a model of a custom electric heating system: R₁- 120 V R2 1. Determine the voltage across each resistor (heating element). R4 www www R34 R₁ = 60 R₂ = 40 R3 = 100 R4 = 120

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter19: Special-purpose Outlets-water Pump, Water Heater

Section19.2: Water Heater Branch Circuit

Problem 4R: The heating elements in electric water heaters are generally classified into two categories. These...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

2. Determine the current flowing through each element.
(Werstmalts
3. Find the power dissipated by each element and the total power dissipated by the heating system.
4. Determine the total power delivered by the voltage source using P=VI.
Related equations
V = IR
V²
P = VI = I²R:
R
*Indicate all assumed voltage polarities and current directions

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