Q3) A 2 kg aluminum block and a 6 kg copper block are connected by a light string over a frictionless pulley. The two blocks are allowed to move on a fixed steel block wedge (of angle 0 = 35°) as shown in the Fig. (1). The coefficient of kinetic friction for each block is shown in the figure. Determine: %3D (a) The acceleration of the two blocks. (b) The tension in the string. Aluminum Сopper H = 0.47 Steel H= 0.36 rrrr

Q3) A 2 kg aluminum block and a 6 kg copper block are connected by a light string over a frictionless pulley. The two blocks are allowed to move on a fixed steel block wedge (of angle 0 = 35°) as shown in the Fig. (1). The coefficient of kinetic friction for each block is shown in the figure. Determine: %3D (a) The acceleration of the two blocks. (b) The tension in the string. Aluminum Сopper H = 0.47 Steel H= 0.36 rrrr

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Fig.( a) shows a steel wire 1 mm diameter is stretched horizontally between two fixed points apart. A vertical load applied at the mid span of the wire causes a vertical displacement of 45 of the point of application of the load applied. What will be the stress induced in the wire and load applied? Neglect the weight of the wire. Take E for the wire material as 200 GN/m². F L 1 m P S N -1 m- M
3) The rigid horizontal bar AB is supported by three vertical rods as shown in the figure and carries the load of 110 kN. The system is stress free before the load is applied. After the load was applied, the temperature of all wires is raised by 20°C. Use a = 12x10-6/°C for steel, a = 18x10-6/°C for copper and a = 20x10-6/°C for brass. Neglecting the weight of the bar AB, determine the location of the 110 kN force in order that AB remains horizontal. copper bar: A=195mm? steel bar: brass bar: A=130mm? A=325mm? A C B 110 kN 3.00m 2.00m 1.80m _ 1.20m 1.50m
Problem 3: Put 32.5 into a steel tube 2.4 meters long, 34 mm radius and 1.5 mm thick. A circular bar made of aluminum with a radius of mm is inserted and these two materials are they are linked together to form a cross section that will work. This cantilever beam obtained from end A it is fixedly supported. This cantilever beam, A torque of T = 900 Nm from end B (torque) is applied. Stiffness modulus of steel, Ge 2.4 m 77 GPa and the modulus of stiffness Gal = 26 for aluminum Since GPa is the rotation at point B What is the (torsion) angle? Calculate.
A 50 mm diameter cylindrical aluminum block is connected to 2 hollowed cylindrical steel blocks as shown in Figure Q1. Both hollowed steel cylinders are of 60 mm and 40 mm outer and inner diameters respectively. The assembly is then connected to a rigid steel plate. Four bolts of diameter 10 mm are then used to rigidly fix the assembly to a wall. A force P is then applied to the assembly. The Modulus of elasticity(E) of steel is 200 GPa while aluminum has Modulus of elasticity(E) of 70 GPa. Both steel and aluminum have a yield strength(oy) of 250 MPa. The bolts have a yield stress (oy) of 800 MPa. All connections and joints are considered rigid. Q3 Determine the allowable value of P that can be applied to the assembly taking into consideration the yielding of all parts of the assembly and bolts. Use a factor of safety of 1.5. b. a. Based on the value of P obtained part (a), determine the total elongation of the cylindrical steel block. Based on the value of P obtained in part (a),…
G6//The light rigid bar ABCD shown in Figure is pinned at B and connected to two vertical rods. Assuming that the bar was initially horizontal and the rods stress-free, determine the stress in each rod after the load after the load P 20 KN is applied. Steel L=2m A=250mm 4m E=200Mpa Aluminum L=2m A=500mm 2m 2m E-72Mра P=20KN
5) A flanged bolt coupling consists of 8 10mm diameter steel bolts evenly spaced around a bolt circle 300mm in diameter and 6 14mm diameter aluminum bolts on a concentric bolt circle of 200mm diameter. Determine the maximum torque that can be applied without exceeding a shearing stress of 50 MPa in the steel bolt and 30 MPa in the aluminum bolts. Use G = 83 GPa for steel and G = 28 GPa for aluminum.
A uniform bar 1 is connected to a tapered rod 2. Both are subjected to axial loads as shown. If P 7 kN, Determine the axial deformation of tapered rod 2 (in mm). Indicate negative sign if compression. 5P E-160 EPa 3P E-200 GP gomm o mm somm mm 30 mm 30 m 30 mm 80 mm
An aluminum rod is rigidly attached between a steel rod and a bronze as shown. Axial loads are applied at the positions indicated. Find the stress of each rod in MPa. Steel Aluminum Bronze A- 500mm A = 400mm? A- 200mm 40KN 10KN 20KN 1.5m 2.5m 2.0m Determine the change in length of steel rod having a length of 800mm and a diameter of 6.5mm. The rod is subjected to a force P equal to 110KN. Young's Modulus is 200GPA Compute normal strain of the rod
A uniform bar 1 is connected to a tapered rod 2. Both are subjected to axial loads as shown. If P = 7 kN, Determine the axial deformation of uniform bar 1 (in mm). Indicate negative sign if compression. 5P E-10 GPa + 39 E-200 GPo 3M 80mm 30 mm 30mm 80 mm 30 mm 30 mm
The cantilever beam shown is an aluminum pipe that has an outside diameter of 114 mm and an inside diameter of 97.3 mm. A moment of 3 kN-m is applied at the free end. Find the rotation at the free end of the pipe. Neglect the weight of the pipe. М 33KN.m 2m Mod. of Mod. of Coeff, of Elasticity Rigidity G Thermal Ultimate Strength Density kg /m3 x 10 Tensile Yield Strength F, MPa Expansion a m/m/C x 10-6 Poisson's MPa MPa MPa Ratio Material x 10 x 10 Tens. Comp. Shear Steel ASTM A36 or A501 7.85 207 83 250 400 11.7 0.25 Steel (high-strength low-alloy) ASTM A992 7.85 207 83 345 450 11.7 0.25 Steel AISI 1020 hot-rolled 7.85 207 79.3 210 380 11.7 0.25 Steel AISI 1040 hot-rolled 7.85 207 79.3 290 520 11.7 0.25 Stainless steel 7.85 200 80 280 580 410 11.7 0.25 (annealed) Cast iron (gray) 7.21 103 41 140 550 220 10.6 0.26 Aluminum allov 2.64 70 28 240 260 190 23.6 0.33 6061-T6 Magnesium alloy 1.794 45 17 210 280 140 26.1 0.34 Titanium alloy 4.40 114 45 900 970 690 9.7 Nominal Outside Inside…
Question 2 A compound shaft consists of copper rod of 30 mm diameter enclosed in a steel tube of external diameter 50 mm and 10 mm thick. The shaft is required to transmit a torque of 1000 Nm. Find the shear stresses developed in copper and steel, if both the shafts have equal lengths and welded to a plate at each end, so that their twists are equal. Take modulus of rigidity for steel as twice that of copper.
Bronze 2 m Steel 1.0 m A H0.6ml-1.0 m- -0.8 m→ 50 kN The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the stress in each rod caused by the 50-kN load, using the following data: Steel Bronze Area (mm?) E (GPa) 600 300 200 83