Q2/ (a) From the expression X = ( ((AB*+C)(AC+B*))*+A ) where '*' indicates the complement (i) Draw the logic diagram? (ii) Write the truth table?
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Q2/
(a) From the expression X = ( ((AB*+C)(AC+B*))*+A ) where '*' indicates the complement
(i) Draw the logic diagram?
(ii) Write the truth table?
(b) For the product of maxterm expression Y(A, B, C)=ΠM (0, 1, 3, 5, 7), write the Standard POS expression (in terms of A, B, C) and draw the truth table?
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- 3. Given the Boolean expression a'b + a'c' + abc, a. Convert the expression to the other standard form. What do you call this standard form? b. Derive its canonical form. What do you call this canonical form? C. Derive the other canonical form. What do you call this canonical form? d. Provide the truth table of the expression e. Draw the logic circuit diagrams of the 2 standard forms(a) Simplify the following Boolean expression 'A' and draw the logic diagram for the simplified expression. A = (X +Y). (X.(Y+X)) (b) Convert the given standard SOP expression, Y(A, B, C)= Em (0, 1, 2, 4, 5) into standard POS expression. (C) Draw the logical diagram of 4 to 1 Multiplexer and write its Boolean expression.Determine the simplified Sum-of-Product (SOP) and Product-of-Sum (POS) expression for the given expression by using Karnaugh map. Draw the simplified logic circuits. f(A, B,C, D) = 7M(3,7, 12,13,14, 15) D(5, 6, 11) Given the Boolean expression as below. Minimize the expression for K(A,B,C) using Boolean algebra and De Morgan's theorems. Draw the simplified logic circuit. К(4, В, С)%3(4Ө В)+ B(А+С)
- Q=[[A.B.C)+[(A+B+C). (A.B.T)]] Prepare the truth table for the above function. Then, write the function you obtained according to POS (maxterm) using Karnaugh Method (without further simplification of the function you obtained from Karnaugh, that is, as you obtained from Karnaugh) and draw the logic circuit (logic circuit) of the function you obtained. Make sure that the circuit you have drawn is understandable, the function you have written, the truth table and the Karnaugh map are readable.A majority gate is a digital circuit whose output is 1 only if the majority of inputs are 1 otherwise the output is 0 for all other cases. Design a combinational logic circuit for 4-input majority gate. a. Construct the Truth table. b. Minimize POS Expression using K MAP c. Draw the combinational circuit for minimize POS1. Given the Boolean expression (b + d)(a’+ b’ + c),a. Convert the expression to the other standard form. What do you call this standard form?b. Derive its canonical form. What do you call this canonical form?c. Derive the other canonical form. What do you call this canonical form?d. Provide the truth table of the expressione. Draw the logic circuit diagrams of the 2 standard forms
- Simplify the expression f (A,B,C,D) = Sm (0,1,4,8,9,12,14,15) using K– map and realize the final expression using basic logic.(a) Simplify the following Boolean expression 'A' and draw the logic diagram for the simplified expression. A = (X + YZ) + (X Y ) (b) Convert the given standard SOP expression, Y(A, B, C)= Em (0, 1, 2, 3, 5) into standard POS expression. (c) Draw the block diagram of 4 to 1 Multiplexer and write its truth table. (Note: The handwritten solution for all parts of this question with all steps should be scanned, and uploaded to Moodle via the submission link).4. Draw the logic circuit realization of the following Boolean expression as stated. Do not simplify! f (A, B, C) = (A + B) + (B + C)
- Boolean Function F(A,B,C,D) = { m (1,2,5,8,11,15), don't cares d(A,B,C,D) = { m (3,10) a. Using a K-map simply F in S.O.P. form b. Draw the logic circuit c. Using a K-map simply F in P.O.S. form d. Draw the logic circuit e. Which form has a lower gate input cost?Simplify the following Boolean Expression and Implement the simplified Logic diagram with Truth Table and Expected Output. Z = (A + B + C + D)(AB CD)Simplify the following Boolean function F, together with don’t care conditions d, and then express the simplified function in sum-of-minterrms form. After getting the simplified Boolean expression, draw a combinational logic circuit for it.F(w, x, y, z) = ∑(4, 12, 7, 2, 10) d(w, x, y, z) = ∑(0, 6, 8)