Boolean Function F(A,B,C,D) = m (1,2,5,8,11,15), don't cares d(A,B,C,D) = { m (3,10) a. Using a K-map simply F in S.O.P. form b. Draw the logic circuit c. Using a K-map simply F in P.O.S. form d. Draw the logic circuit e. Which form has a lower gate input cost?
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- Simplify the following expression using Karnaugh map and implement. Draw simplified logic diagram as well. Implement on Multisim software. (a) Y=A.B.C'.D+A.B'.C'.D+A'.B'.C'.D+A'.B.C'.D+A'.B'.C'.D'+A'.B.C'.D'+A'.B.C.D'+A'.B.C.D+A'.B'.C.DConsider the multiplexer based logic circuit shown in the figure MUX MUX 1 Select one: a. W S1' S2' O b. W + S2 + S1 c. WS1 + WS2 + S1 S2 O d. WeS1es2Electrical Engineering Task Figure shows a BCD counter that produces a four-bit output representing the BCD code for number of pulses that have been applied to the counter input. In particular, the DCBA outputs will never represent a number greater than 1001,-91, (MOD-10). (MSB) Logic BCD counter circuit HIGH only when DCBA=210-310, or 910 a. Draw the logic circuit using the minimum expression and then explain its operation. B
- Consider the circuit below. The switches are controlled by logic variables such that, if A is high, switch A is closed, and if A is low, switch A is open. Conversely, if B is high, the switch labeled is open, and if B is low, the switch labeled is closed. The output variable is high if the output voltage is 5V, and the output variable is low if the output voltage is zero. a. Write a logic expression for the output variable. b. Construct the truth table for the circuit. A Logic 1 5V(+ B C Logic 0 Ranswere fast please question from DIGITAL LOGIC DESIGN TOPIC : Designing Combinational Logic You are designing a water level circuit using 74ALS151 (8 to 1 Multiplexer IC)* When input is 0000 that means tank is empty.* When input is 1111 that means tank is full.* When input is below 5, that means water level is low.* So, make a circuit using 74ALS151 Multiplexer IC that shows a "low water" indicator light(by setting an output L to 1) when the water level drops below level 5.Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).
- (a) A logic circuit shown in Figure Q.3 has a 4-bit input A and B, three 4-bit wide 2:1 muxes, a 4-bit adder, a 4-bit output F, and a carry flag C. For the given Table Q.3, fill in the value of output F and carry flag C for the given value of A, B, S0, S1 and S2. 51 52 1001 Flag C 0011 Figure Q.3 Table Q.3 A So S1 S2 F Flag C 0001 1000 0010 1001 1 1 0011 1101 0100 1101 1110 0111 1Q5: Determine the output boolean expression for logic circuit as shown in figure below. x- y- D z-Q1/ Draw the logic circuit after simplify the circuit show below using K. map: A Y. C- Add filo B.
- Design a combinational circuit with the four inputs A,B.C, and D, and three outputs X, Y, and Z. When the binary input is odd number, the binary output is one lesser than the input. When the binary input is even number the binary output is one greate than the input. Implement the function using multiplexers with minimal input and select line.Electrical Engineering Verilog Design N-bit binary counter which counts the number from 0 to 2N-1. After reaching to maximum count i.e. 2N-1, it again starts the count from 0. i. Write the description of the counter in Verilog ii. Generate the design from the listing ii. Produce the waveforms of the counterii) For the circuit shown in Figure B9, a. Find logic functions for Y and Z. b. Simplify function Z using Boolean algebra. Y Figure B9 AB