Q1) If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL Find the physical address in the memory. 10:1
Q: (a) Set a base address for a generic PIO at 0x10008000 called pioBase. Assume this is just an 8-bit…
A: Change in memory location an interrupt is set to send signals, when we change in memory.
Q: 3. Translate following program into compiled MIPS code. Assume that g, c, i are in $s0, $s1, $s2…
A: Given: We have to translate the following program into Compiled MIPS code . Assume that g, c , i…
Q: if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical…
A: The answer will be:- 6234H
Q: e instruction, Add #45,R1 does Adds 45 to the value of Rl and stores it in R1 Adds the value of 45…
A: Add #45, R1 is instruction for addition.
Q: 2.12 Assume that registers $s0 and $s1 hold the values 0x80000000 and OXD0000000, respectively.
A:
Q: CPU Datapath The following figure shows the overall datapath of the simple 5-stage CPU we have…
A: ANSWER: a) MUX 1 Input 1: Register A input 2:Register B b) MUX 2 Input 1: Register C input…
Q: 7. Suppose that. DS = 0200H, BX = 0300H, and DI = 400H Determine the memory address accessed by each…
A: Given data, DS= 0200H BX= 0300H DI= 400H To find :- Memory address for following instructions at…
Q: 3) The physical address is the actual location within the RAM. It is pu bus by the CPU to be decoded…
A: 1. Logical address =CS:IP =426:A436 2.offset address = IP…
Q: 2. a) Explain the following code and indicate in each case the type of addressing mode used. i) СМА…
A: Given second step different types of instructions are explained, addressing mode of 8086are…
Q: 7-lf we assume we place the following MIPS code starting at location 8000 in memory, what is the…
A: 1) SLT $t2 $zero $t0 Binary: 00000000000010000101000000101010 Hex: 0x0008502a 2) BNE $t2 $zero…
Q: onsider the code sequence below lw $t1, 4($t0) add $s2, $t1, $t2 lw $t3, 16($t0) add $s3,…
A: Memory operands - Data transfer command: A command to move data to and from memory Registered…
Q: Let R15=0x0000 00FF. The contents of the memory location at an address equal to the last 5 digits of…
A: R15 =0x0000 00FF. The contents of the memory location at an adress equal to the last digits of your…
Q: (B) - Identify the addressing mode for the following instructions then compute the physical address…
A: The physical address of any instruction can be calculated by the formula: PA =Segment reg…
Q: Assume the following contents of registers and quadwords in memory: Location Value %rax Ox8 %rbx Ox1…
A: leaq s,d Here, “s” denotes source, “d” denotes destination. This instruction loads the address of…
Q: Q1: what is the addressing mode for the following instructions: 1. SUB A,B,C 2. OR A,B 3. ADD R1 4.…
A: Instructions Addressing Mode Explanation 1. SUB A,B,C Implied addressing mode The SUB is a…
Q: Discussion: 1. Two bytes - sizcd BCD integers are stored at the symbolic addresses NUMI and NUM2…
A: Instruction sequence to generate the difference (NUM2-NUM1) and storing it at NUM3
Q: 1) Write simple instructions (simple program) that will add two consecutive bytes of data storied…
A: Ans 1) CMP and SUB, both the instructions subtract one from the other. But the difference is, CMP…
Q: Assume the following values are stored at the indicated memory addresses and registers: Address…
A: Firstly movl moves a long (32-bits) from source to destination. Here we are given :
Q: 1. The hypothetical machine of Figure 3.4 also has two I/O instructions: In these cases, the 12-bit…
A:
Q: 3.i) Assume that the following registers contain these hex contents: RO = 0XF123, RI - 0x3456, and…
A: Answer: I have given answer in the handwritten format.
Q: 14- Change the content of memory location [300h] to FFh without using MOV instruction. Use just one…
A: Algorithm : Move 300h into CX register Move CX into DS segment (now we are in 300h data segment)…
Q: (i) Identify the addressing mode used in each instruction in the following code segment, and give…
A: The way of specifying data to be operated by an instruction is known as addressing modes. This…
Q: 1) into the data memory at address stored in ($s0). Hint: In this problem, the third byte value in…
A: Note: We are given the data in bytes so de defined the variable size by bytes "db"
Q: Q:find the actual address for the ..il following instruction assume X=38 and R index=DDCE8 hex LOAD…
A: Given: X = 38 Ri = DCE8
Q: Q:find the actual address for the following instruction assume X= (27)hex and R index=DBC9 LOAD…
A: Question:
Q: 8086Microprocessor 1. Write a piece of code that exchanges a block of 236 bytes stored at locations…
A: Write 8085 code exchanges a block of bytes to another block Algorithm: Take a count equal to 256…
Q: To get the physical address from the logical address generated by CPU we use ____ . a. MAR b. MMU c.…
A: Task :- Choose the correct option for given question.
Q: 22. Suppose that DS = 0200H, BX = 0300H, and DI = accessed by each of the following instructions,…
A: The Answer is
Q: 1) Write simple instructions (simple program) that will add two consecutive bytes of data storied…
A: In Direct addressing mode, we directly give the address of the location, where we want to retrieve…
Q: QI) I BX=1000, DS-0200, SS=0100, CS-0300 and AL=EDH, for the following instruction: MOV [BX] +…
A: Here is Solution for Above Problem :: Q1). Given Data : BX = 1000 DS = 0200 SS = 0100 CS = 0300 AL…
Q: QUESTION ONE (1) 1. The hypothetical machine has two I/O instructions: 0011 = Load AC from I/O 0111…
A: 34 Opcode Address (a) Instruction format Magnitude (b) Integer format Program counter (PC) = Address…
Q: Write simple instructions (simple program) that will add two consecutive bytes of data storied with…
A: In a direct addressing mode, the data to be worked upon is in a memory location and as an operand,…
Q: The states of the instruction cycle involve operand address calculation which means that the…
A: Algorithms and algorithmic problem resolving that can concern as a central place in computer science…
Q: Q:find the actual address for the following instruction assume X=38 and R index=DCE8 hex LOAD X(Ri),…
A: Solution:-
Q: (B)- Identify the addressing mode for the following instructions then compute the physical address…
A: 1)LDS [FFH],SI Register indirect addressing mode. In this addressing mode, The address field of…
Q: Microprocessor Hw Q1 Execute the following code and show the contents of the registers: LDI R16,$03…
A: A CPU or processor register is one of a small set of data holding places that are part of the…
Q: Question 4 Endianness Assume that a snippet of memory is shown below (in hex), starting with the…
A: 4. Given, Address starts with 0x10. Data is : | 77 | AB | 69 | CA | 0D | F0 | 12 | BE | The system…
Q: 2. a) Explain the following code and indicate in each case the type of addressing mode used. i) CMA…
A: This insertions are related to microprocessor. Above question explained in step send.
Q: Explain utiat haprns PUSH Bx instruction executes. Make sure to show where BH and BL are stored…
A: Hey there, I am authorised to answer any one question at a time when there are multiple questions…
Q: Instruction Description LD RI, 45(R2) Read data from memory and store in R1. Memory address is…
A: Answer:-
Q: Example: The content of PC in the simple computer is 3AFU. The content of AC is 6ECSH. The content…
A: List of the initial conditions that are given below: AR IR 3AF 932E 32E 09AC…
Q: Q3/ Design a machine with a byte addressable main memory of 216 bytes and block size of 8 byte.…
A: Given that, Size of main memory= 216 bytes Block size= 8 bytes Number of lines= 32
Q: 8 Find the physical address of the memory locations referred in the following instructions if…
A: 8086, via its 20 bit address bus, can address 220 = 1,048,576 or 1 MB of different memory locations.…
Q: Write at most two instructions to move ONLY the fourth byte value in the register ($s1) into the…
A: This is how you can do this easily. Note: We are given the data in bytes so de defined the variable…
Q: 52-Two word wide unsigned integers are stored at the physical memory addresses 00A00 and 00A02,…
A: Given:- Two word wide unsigned integers are stored at the physical memory addresses 00A00 and 00A02…
Q: 1- The instruction : MOV [Dx+SI], Ax is allowed T 2- The instruction : MOV ES:[SI], Ax is not…
A: 1. True The instruction is valid 2. False The instruction is invalid, since in based index…
Q: For the MIPS assembly instructions below, what is the corresponding C statement? Assume that the…
A: Actually, registers are used to stores the data/information.
Q: iv) Using the following instruction format, a total of registers can be addressed 8 7 10 OP code…
A: 4) 4.10
Q: 2. MIPS C a. (.. -) Implement the following code in MIPS assembly. Assume variables 'm' and 'n' are…
A:
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- The memory location at address of 0X003FB01 contains 1-byte memory variable J (0010_0001), and the memory location at the address of 0X003FB02 contains 1-byte memory variable K (0001 0010), see figure below. There is a 2-byte variable M which hold binary information M (1110 0101 0000 1i11). What is the address in hexadecimal format for 2-byte memory variable M, following little Endian computer? 7 Address in Data in Hex. Format Hex. Format 0X003FBF04 1110 0101 M OX003FBF03 0000 1111 0X003FBF02 0001 0010 0X003FBF01 0010 0001 J Its address in hexadecimal is 0X003FBF02. а. Its address in hexadecimal is 0×003FBF03. O b. Its address in hexadecimal is 0X003FBF04. Its address in hexadecimal is 0×003FBF01. d.LAX]= 1000H, [BX]= 4000H, [SI]=3000H, [DI]= 4000H, [BP] = 5000H, [SP] = 6000H, [CS]=0000H, [DS]=9000H, [SS]= 2000H, [IP]= 7000H. MOV AX, [3F27H] * O physical address 94000H O physical address 97000H O physical address 93F27H MOV DX, [BX] * physical address 94010H physical address = 94006H O physical address 94000H MOV AX, [BX + SI] * physical address = 97000H physical address 97030H O physical address 97005HLet's say p contains a memory address and the 8 bytes in memory beginning at that address are (in hex): 01 12 23 34 45 56 67 78. If p's type is "uint32_t *", what is the value of x on a little-endian computer after executing: uint32_t x = p[0]; Ox01122334 Ox0112233445566778 Ox34231201 Ox7867564534231201 O O O O
- Student information is being held in a data area, where each student record has the following format: The first nine bytes are the student number, held in ASCII The next byte is the course mark The next word is the section identifierThere are well over three hundred such student records that have been loaded sequentially into memory starting at address $10000. The last record loaded is a dummy record with a section identifier of $FFFF, to show the end of the records.Write an assembler subroutine GetMax that will scan the entire list and find the highest mark. If there is a tie, the first student in the list with the highest mark should be found. The subroutine should return the starting address of this record in address register a3.Let's say that p is a pointer to memory and the next six bytes in memory (in hex) beginning at p's address are: aa bb cc dd ee ff. What value would be in x if the following code is run on a little- endian computer? uint16_t *q uint16_t x = (uint16_t *)p; q[0]; aa aabb bbaa aabbccdd ddccbbaaLet's say p contains a memory address and the 8 bytes in memory beginning at that address are (in hex): 01 12 23 34 45 56 67 78. If p's type is "uint32_t *", what is the value of x on a big-endian computer after executing: uint32_tx = p[0]; Ox01122334 Ox0112233445566778 Ox34231201 Ox7867564534231201 O 0 0 O
- Write a C code to perform vector arithmetic: Define 3 vectors A[100], B[100], C[100]. Get n from as a command line argument. Example if n=10, then (./vector 10), and create n processes. (n will be one of Divisors of 100). Get operation from user: add, sub. Each process will create a number of threads. Number of threads per process = 100/(10 number of processes). Perform the operation on a chunk of the vector, for example, if n = 10, each process will create (100/10*10=1) 1 thread to add\sub 10 elements. Use execl to run the add or sub programs Parent should print A.B.C in a file. (yourname.txt) For example, n=5, operation sub Partition work equally to each process: PO create (100/10*5=2) 2 threads → Thread00 will executes A[0:9] B[0:9]-C [0:9] = Thread01 will executes A[10:19] B[10:19]-C[10:19] = PI create (100/10*5=2) 2 threads → Thread 10 will executes A[20:29] = B[20:29]-C [20:29] Thread11 will executes A[30:39] B[30:39]- C[30:39] = and so on. no…Suppose that you have a UNIX file system where the disk block size is 4096 bytes. Disk addresses and file block pointers take 32 bits (4 bytes), and the i-node contains 12 direct pointers, one single-indirect pointer and one double-indirect pointer. Assume an index block is the same size as a data block (both 4096 Bytes). If there is a file having 50,000 bytes of data and it is never been accessed, we only assume the file's i-node is in memory, but none of the rest of the file. If the user process wants to access to read the entire file into the memory, how many I/O operations would be needed? O a. 15 O b. 12 O c. 14 O d. 132. Implement the frame replacement algorithm for virtual memory In Java For this task, you need to perform the simulation of page replacement algorithms. Create a Java program which allows the user to specify: • the total of frames currently exist in memory (F), the total of page requests (N) to be processed, • the list or sequence of N page requests involved, For example, if N is 10, user must input a list of 10 values (ranging between 0 to TP-1) as the request sequence. Optionally you may also get additional input, the total of pages (TP) This input is optional for your program/work. It only be used to verify that each of the page number given in the request list is valid or invalid. Valid page number should be within the range 0, .. , TP-1. Page number outside the range is invalid. Then use the input data to calculate the number of page faults produced by each of the following page replacement algorithms: • First-in-first-out (FIFO) - the candidate that is the first one that entered…
- Suppose that DS=1000H, SS= 2000H, CS=3000H, ES=4000H, BP=FFH, BX=FFFFH and DI=5H.i. Which memory locations are addressed by: MOV DL, [BP]?ii. Which memory locations are addressed by: MOV EAX, [BX+DI]?Consider the following image that represents part of the memory of a 16-bit address space that has an addressability of 2 bytes (like LC-3): A memory location can store an address. We call that memory location's contents a "pointer" since it's an address that "points" to another memory location. G.) Interpret the contents at address 0x0C0B as a pointer. (Enter hex like the following example: 0x2A3F) H.) What are the contents of the memory location that the pointer above is pointing to? (Enter hex like the following example: 0x2A3F) Another reference : LC-3 Opcodes in Hex ADD 0x1 JMP 0xC LDR 0x6int i; float x[5], y[5]; [ lots of code deleted... ] for (i=0;i y[i]) x[i] = x[i] + y[i]; [ more code deleted... ] Translate to MIPS assembly language: