Let's say that p is a pointer to memory and the next six bytes in memory (in hex) beginning at p's address are: aa bb cc dd ee ff. What value would be in x if the following code is run on a little- endian computer? uint16_t *q (uint16_t *)p; uint16_t x = q[0]; aa aabb bbaa aabbccdd ddccbbaa

Let's say that p is a pointer to memory and the next six bytes in memory (in hex) beginning at p's address are: aa bb cc dd ee ff. What value would be in x if the following code is run on a little- endian computer? uint16_t q (uint16_t )p; uint16_t x = q[0]; aa aabb bbaa aabbccdd ddccbbaa

Name: Let's say that p is a pointer to memory and the next six bytes in mem
Uploaded: 2024-03-20T06:51:23.000Z
Channel: Bartleby
Description: Let's say that p is a pointer to memory and the next six bytes in memory (in hex) beginning at p'saddress are: aa bb cc dd ee ff. What value would be in x if the following code is run on a little-endian computer?uint16_t *quint16_t x =(uint16_t *)p;

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter12: Points, Classes, Virtual Functions And Abstract Classes

Section: Chapter Questions

Problem 19SA

See similar textbooks

Similar questions

What is the correct way to assign the pointer p to the address of x?. Single choice. p = %x; p = &x; &p = *x; *p = &x;
The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.
The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.#include <stdio.h>int main( ){ char c = 'Z'; char *cp = &c; printf("cp is %p\n", cp); printf("The character at cp is…
Please choose which of these are true about pointers. Check all that apply. Wrong answers will subtract points. O A pointer contains an address in RAM. The pointers we studied were mainly variables. O A pointer can be initialized with a special value called nullptr. In the material we studied, we saw that a pointer can contain an entire array. This definition: double * dp; means that the dp variable can contain a double. Assume this is a function heading for the code you will write: void somthing10 (int * ptr) a. In one line of code, how could you add 10 to what ptr points to? b. Assume ptr points to the first element in an array of ints, each of which takes up 4 bytes of memory in RAM. In one line of code, how could you store 10 into the third element in the array? If this is not possible, enter "np"
Assuming the pointer is 4 bytes in length and the int is also 4 bytes in length, choose the most accurate response from the provided choices. A Only i) would compile successfully and it would return size as 4. B i), ii) and iii) would compile successfully and size of each would be same i.e. 4 C i), ii) and iii) would compile successfully but the size of each would be different and would be decided at run time. D ii) and iii) would result in compile error but i) would compile and result in size as 4.
The program below uses pointer arithmetic to determine the size of a 'char' variable. By using pointer arithmetic we can find out the value of 'cp' and the value of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic: adding one to a pointer makes the pointer point to the next element of the same type. For a pointer to a char, adding 1 really just means adding 1 to the address, but this is only because each char is 1 byte. Compile and run the program and see what it does. Write some code that does pointer arithmetic with a pointer to an int and determine how big an int is. Same idea – figure out how big a double is, by using pointer arithmetic and printing out the value of the pointer before and after adding 1. What should happen if you added 2 to the pointers from exercises 1 through 3, instead of 1? Use your program to verify your answer #include <stdio.h>int main( ) { char c = ‘Z’; char *cp = &c; printf("cp is 0x%08x\n", cp); printf("The character…
Numbers between 0 and 15 are stored in the memory location starting from physical address B000Fh randomly. Write a program which finds the element order number in the string starting from 0 to 15 and writes to physical address C000Fh. (Eg: "1" is 2nd element in the first string, "2" is 4th element, ....etc)
The standard library function calloc(n,size) returns a pointer to n objects of size size, with the storage initialized to zero. Write calloc, by calling malloc or by modifying it.
Computer Science Write a C program that calls malloc() 1001 times allocating blocks of size 4 each. Use type char * to store the pointers returned by malloc(). When done, print the difference in the addresses of the first and last block allocated. This difference is the amount of memory malloc actually used to create 1000 blocks of size 4. It is a lot more than you would expect. Repeat this for other block sizes and make a table of your results. Do you see any pattern? Any guesses why?
If you want to define integer far pointer *n to address (Ox2000;0x200) O int far *n=(int far*)MK_FP(0x2000,0x200); O int far *n=(far int*)MK_FP(0x2000,0x200), int far *n-(int far*)MK FP(0x2000:0x200), O int far *n=(far int*)MK_FP(0x2000:0x200);
Problem Y: Implement the reader writer problem using pthreads and semaphores. You should allow multiple readers to read at the same time and only one single writer to write to the data set. You are required to use the following: 1. A semaphore rw_muter initialized to 1. 2. A semaphore muter initialized to 1. 3. An integer reader_count initialized to 0.
Write a program to find the number of times that a given word occurs in a sentence using pointers. Read data from standard input. The first line is a single word, which is followed by general text on the second line. Read both up to a new line character, and insert a terminating null before processing. Typically output should be : The word is “ the ”. The sentence is “ the cat on the mat “ . The word occurs 2 times. IN C LANGUAGE