Q: For a basic computer that is currently running in its timing TO of execution for an instruction that is located in memory location 366. The content of AC is (212) and the content of memory locations are as follow: [memory location: content]: [365:9473], [366:7010], [367:5431], [368:4620], [431:1A23], [620:C80D]. Answer the following questions that examine the contents of PC, AR, AC, DR and IR after the end of execution for the next instruction. (.(Note: all numbers are in Hexadecimal

Microsoft Visual C#
7th Edition
ISBN:9781337102100
Author:Joyce, Farrell.
Publisher:Joyce, Farrell.
Chapter8: Advanced Method Concepts
Section: Chapter Questions
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Q: For a basic computer that is currently running in its
timing TO of execution for an instruction that is located in
memory location 366. The content of AC is (212) and the
content of memory locations are as follow: [memory
location: content]: [365:9473], [366:7010], [367:5431],
[368:4620], [431:1A23], [620:C80D]. Answer the following
questions that examine the contents of PC, AR, AC, DR
and IR after the end of execution for the next instruction.
(.(Note: all numbers are in Hexadecimal
The content of AR after the end of
* :execution for the next instruction is
368
431
None of the choices
432
620
Transcribed Image Text:Question Q: For a basic computer that is currently running in its timing TO of execution for an instruction that is located in memory location 366. The content of AC is (212) and the content of memory locations are as follow: [memory location: content]: [365:9473], [366:7010], [367:5431], [368:4620], [431:1A23], [620:C80D]. Answer the following questions that examine the contents of PC, AR, AC, DR and IR after the end of execution for the next instruction. (.(Note: all numbers are in Hexadecimal The content of AR after the end of * :execution for the next instruction is 368 431 None of the choices 432 620
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