Problem 2.6 - Express the force F in terms of x, y, and z and z components
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- ASAPReplace the force system by a single force resultant and specify its point of application, measured along the x axis from point P. Given: Fj = 125 N a = 1 m F2 = 350 N b = 3 m F2 F3 = 850 N c = 1.5 m d = 2 m a 1) Find FCR) = N. (+ Point up point down] 2) find distance bet ween FrR) and PQ1: In the Figure 1, two forces (P & Q) are acting on the same fixed point A. Find the resuitant of these forces and its angle with the horizon by using: (a) Graphical solution. (b) Trigonometric solution. Q = 60 N Figure 1: P= 40 N 65 35
- The rectangular plate shown weighs 93 lb and is held in the position shown by hinges at A and B and by cable EF. Assuming that the hinge at B does not exert any axial thrust and no couples exerted on both A and B, determine (a) the tension in the cable, (b) the reactions at A and B. y Solution: 12 in. 30 in. H 4 in. E 8 in. B 4 in. 25 in. 20 in. XQ1:For the force system as shown in figures below ,Find the magnitudeof the equivalent concentrated load; (Resultant force) and its location asmeasured from point A.Q2/ For the force (F), the rectangular components are Fx - -40 N. and Fy = 60 N, respectively. Determine the non-rectangular components of the force (F) in the y- and h-direction, 30° h t Add file
- What would be the resultant force Fof the triangular distributed load and its location d measured from point A. 90 lb/ft 3 ft 5 ft 2 ft > Select one: O a. F= 225 Ib and d= 3.67 ft O b. F= 300 Ib and d=2.5 ft O C.F= 450 ib and d=3.67 ft O d. F= 300 Ib and d= 1.67 ftWhat would be the resultant force F of the triangular distributed load and its location d measured from point A 60 lb/ft 3 ft * 5ft 2 ft. Select one O F-150 lb and d = 3.33 ft Ob F-300 lb and d = 167 ft Oc F = 300 lb and d - 2.5 ft Od F-150 lb and d = 3.67 ft AWhat would be the resultant force F of the triangular distributed load and its location d measured from point A. 120 lb/ft A 3 ft 5 ft 2 ft Select one: Oa. F= 300 lb and d = 2.5 ft Ob. F= 300 lb and d= 1.67 ft O c. F = 300 lb and d = 3.67 ft O d. F= 600 lb and d = 3.67 ft Finist