Q2/ For the force (F), the rectangular components are Fx -40N. and Fy = 60 N. respectively. Determine the non-rectangular components of the force (F) in the %3D y- and h-direction, 30° F
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- Q2: The shaft S exerts three force components on the die D. Find the magnitude and coordinate direction angles of the resultant force. Force F, acts within the octant shown. F = 200 N 2 60 F 300 N F- 400 NQ1/ A-Given F1 -5.ON 30° N of E F2-7.0N 60° S of W and F3-10.0N 40° E of S. (a) Find the components of each vector. (b) Find the vector components of the resultant force . (c) Find the magnitude and direction of the resultant force.F1=500 kips 69⁰ 0.8 F3=250 kips 1 A F2 3 concurrent forces are acting on a point as shown. What is the positive angle of the resultant from the positive x axis if = 36.2 anf F2-313.9 kips?
- Three forces act on a hook. Determine the magnitude of the resultant of the force. Neglect hook bending. F2 - 1500 N - 1000 N 20 30 16 F3 - 750 N Select one: O a. 1250 N Ob. 1510 N C. 1140 N d. 989 NQI) At point A, the four forces Fs, Fc, Fp and Fe act, the lines of action for these forces are given by the straight lines AB, AC, AD and AF, as shown in Figure 1. Coordinate the points are: A 3 B 2. D 4 12 cm Figure 1 The magnitudes of the forces are: F7 KN, F= 3 KN, F=9 KN and F= 13 KN. Represent this force Facting on the point 4 as a Cartesian vector and determine its direction.2. Determine the following: a) Magnitude of the projected component of along the line of action of F2 b) Angle 0 between the two cables attached to the pipe. F, = MN Ib 120 60° F, = SN Ib 1.5 m 3. The guy wires are used to support the telephone pole. Represent the force in each wire in Cartesian vector form. Neglect the diameter of the pole F= MNN F: = FN N 4 m 2 m D. 4 m 3 m y
- Using the Cartesian components (rectangular components), determine the resultant of the force vectors answering the magnitude in the space provided below and the direction in the procedure document. Only handwritten Draw to approximate scale the sum-of-forces polygon showing the original vectors and the resultant. In a separate document show the entire work. F = 252lbs, F₂ = 130lbs, a = 65° F3 = 55lbs, m = 6.2, and n = 8.6Q2-4- Use the graphical method to find the magnitude and direction of the resultant of these forces F-500 N 700 Na = 1.2 m b = 1,8 m c = 4 m Force AB = 500 Newtons FAB Find the y-component of Force AB in N. If the calculated answer is not whole number, express it in 4 significant figures. If the value is negative, include a negative sign. Find the z-component of Force AB in N. Find the Projected Force to direction AC in N. (Hint: Dot Product).
- a. Determine the magnitude of P and F (in N) if the 45 degrees North of East. (> b. If the components of the resultant force are along the u-axis and a certain v-axis and it is known that the component along the u-axis is 5X0 N at 35° South of East, axis? . right to take le F 8YO N to the the angle of the v-axis with respect 38° eme. Example Student Number (SN) This is not vae own as if it were your own may 202 1 1 36 2 1 35° material. T 3X 4Z0 N my ection under RA 8293. e legal action against 2.1 kN avngtofoRepublic Act (RA) NNN z N NReplace the force system by a single force resultant and specify its point of application, measured along the x axis from point P. Given: Fj = 125 N a = 1 m F2 = 350 N b = 3 m F2 F3 = 850 N c = 1.5 m d = 2 m a 1) Find FCR) = N. (+ Point up point down] 2) find distance bet ween FrR) and PWith the given force F, determine the angle (acute angle) between the Force and the segment AB. Also determine the Force projected along AB, FAB. 1 ft y y F -42 j Ib F 78 k Ib 3 ft y 2 ft 8 ft Answers: Angle in between (acute angle): deg FAB in scalar form: Ib (Absolute Value) FAB in vector form: { i+ j+ k} Ib (include negative sign if necessary)