Problem 1A cannon ball on the ground is fired at 35 with an initial velocity of 250 m/s.a. How long will it take to hit the ground?b. How far from the cannon ball will it hit the ground?c. Compute for maximum height to be reached by the cannon ball.Given:V. - 250 m/s35g- 9.8"Solution:a. The time of flight of the cannon ball2v, sin 500m/s(sin 35°) 500m/s(0.57) _ 28Sm/s = 29.08s9.8m/x9.8m/s9.8m/sb. The range of the cannon ballv, sin 0(250m/s) 2 sin 35° 62500m2/s 2(0.57)9.8m/sR9.8m/ s62.500m /s(0.9397) 58,730.79m /s?9.8m/s5,992.94m9.8m/sc. The maximum height that the cannon ball reachedv sin 0 (250m/s)²(sin 35")(sin35") 62.500m /s²(0.57)2(9.8m/s)Утах2819.6m/s62,500m² /s²(0.32899 20,561.87m /s- 1,049.08m19.6m/s19.6m/sThis time, it's your turn to solve the next problem.Problem 2An arrow is launched at a velocity of 20 m/s in a direction making an angle of 25°upward with the horizontal.10a. How long will it take to hit the ground?b. How far from the cannon ball will it hit the ground?c. Compute for maximum height to be reached by the cannon ball.

Answered: Problem 1 A cannon ball on the ground…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter3: Two-dimensional Kinematics

Section: Chapter Questions

Problem 28PE: (a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by...

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