Q1(a) An object is shot at at 25 degree angle with a velocity of 5 m/s. What is the velocity in the X-direction? Y-direction? Vor= 5cos (25)=4.53s, Voj=5Sin25=2.11"3 (b) Now that you have calculated the initial velocity in the Y-direction we can find the time it takes the projectile to reach its maximum height. We cleverly recognize that at the top the velocity in the y direction is 0 so we can solve: v, = v, sin 0, – gt

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Projectile Motion