Formulas: Work done on a gas: Wgas = - PAV First Law of Thermodynamics: AU = Q+ W Idea gas law: PV = nRT, thus, PAV = NRAT Molar specific heat at constant volume: Cv : AU = nCvAt where n is moles 3 R for monatomic gasses, 2 5 R for diatomic gasses 2 The value of Cv is just: 5 R for monatomic gasses, 2 7 for diatomic gasses 2 The value of Cp is just: Joules Where R is the universal gas constant: R = 8.31 mole-Kelvin Molar specific heat at constant pressure: Q = CPAT CP For adiabatic processes: PVY = constant, where Y Cv Work done at constant temperature: W = -nRT In( 1 The First Law and Thermodynamic Processes (Ideal Gases) Process AU Q W Isobaric nC, AT nC, AT -P AV Adiabatic nC, AT Δυ Isovolumetric nC, AT AU Isothermal -W -nRT In 50.00 moles of a monatomic ideal gas increases in volume as shown below. Its final pressure is 4.50 x 105 Pa. Compute the heat energy, Q, that enters the gas during this process. P(10°Pa) 5.00 4.00 3.00 A 2.00 1.00 V(m³ ) 0.200 0.400 0.600

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter17: Energy In Thermal Processes: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 85P
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Formulas:
Work done on a gas: Wgas
= - PAV
First Law of Thermodynamics: AU = Q+ W
Idea gas law: PV = nRT, thus, PAV = NRAT
Molar specific heat at constant volume: Cv : AU = nCvAt where n is moles
3
R for monatomic gasses,
2
5
R for diatomic gasses
2
The value of Cv is just:
5
R for monatomic gasses,
2
7
for diatomic gasses
2
The value of Cp is just:
Joules
Where R is the universal gas constant: R = 8.31
mole-Kelvin
Molar specific heat at constant pressure: Q = CPAT
CP
For adiabatic processes:
PVY = constant, where
Y
Cv
Work done at constant temperature:
W = -nRT In(
1
The First Law and Thermodynamic Processes (Ideal Gases)
Process
AU
Q
W
Isobaric
nC, AT
nC, AT
-P AV
Adiabatic
nC, AT
Δυ
Isovolumetric
nC, AT
AU
Isothermal
-W
-nRT In
Transcribed Image Text:Formulas: Work done on a gas: Wgas = - PAV First Law of Thermodynamics: AU = Q+ W Idea gas law: PV = nRT, thus, PAV = NRAT Molar specific heat at constant volume: Cv : AU = nCvAt where n is moles 3 R for monatomic gasses, 2 5 R for diatomic gasses 2 The value of Cv is just: 5 R for monatomic gasses, 2 7 for diatomic gasses 2 The value of Cp is just: Joules Where R is the universal gas constant: R = 8.31 mole-Kelvin Molar specific heat at constant pressure: Q = CPAT CP For adiabatic processes: PVY = constant, where Y Cv Work done at constant temperature: W = -nRT In( 1 The First Law and Thermodynamic Processes (Ideal Gases) Process AU Q W Isobaric nC, AT nC, AT -P AV Adiabatic nC, AT Δυ Isovolumetric nC, AT AU Isothermal -W -nRT In
50.00 moles of a monatomic ideal gas increases in volume as shown below. Its final
pressure is 4.50 x 105 Pa. Compute the heat energy, Q, that enters the gas during this
process.
P(10°Pa)
5.00
4.00
3.00
A
2.00
1.00
V(m³ )
0.200 0.400 0.600
Transcribed Image Text:50.00 moles of a monatomic ideal gas increases in volume as shown below. Its final pressure is 4.50 x 105 Pa. Compute the heat energy, Q, that enters the gas during this process. P(10°Pa) 5.00 4.00 3.00 A 2.00 1.00 V(m³ ) 0.200 0.400 0.600
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