1. Consider n moles of gas. If you are to include the finite volume b of a mole, how should you write the equation of state based on the ideal gas equation given that the pressure is p, the volume is V and the temperature is T? A. p(V – b) = nRT B. (p/b)V = nRT C. p(V – nb) = nRT D. bpV = nRT 2. A monoatomic ideal gas un- dergoes several thermodynamic processes as shown in the given pV diagram. Process A → B is an isochoric process while process B →C is an isothermal process. What is the associated work to this series of processes? A. -2.75 (k.J] p (Pa) 12.5 X 10ʻ- A 7.50 X10 B C B. –0.75 (k.J] C. +0.75 [kJ] V(m?) 0.040 0.100 D. +2.75 (k.J) 3. In the pV diagram provided, we have an isobaric process (process ab), an isochoric process (pro- cess bc), and an arbitrary process (process ac). Using the provided values in the table and assuming we have an ideal gas, what is Quc? P2 [ Qab = 150 [J] (into the system) Qbe = 66 [J] (out of the system) Pi = 14 x 10" (Pa] 2 = 20 x 10* (Pa] V = 3 x 10-3 (m] V2 = 11 x 10-3 (n"] A. 60 (J) В. 352 (J) С. 136 [J] D. 216 (J]
1. Consider n moles of gas. If you are to include the finite volume b of a mole, how should you write the equation of state based on the ideal gas equation given that the pressure is p, the volume is V and the temperature is T? A. p(V – b) = nRT B. (p/b)V = nRT C. p(V – nb) = nRT D. bpV = nRT 2. A monoatomic ideal gas un- dergoes several thermodynamic processes as shown in the given pV diagram. Process A → B is an isochoric process while process B →C is an isothermal process. What is the associated work to this series of processes? A. -2.75 (k.J] p (Pa) 12.5 X 10ʻ- A 7.50 X10 B C B. –0.75 (k.J] C. +0.75 [kJ] V(m?) 0.040 0.100 D. +2.75 (k.J) 3. In the pV diagram provided, we have an isobaric process (process ab), an isochoric process (pro- cess bc), and an arbitrary process (process ac). Using the provided values in the table and assuming we have an ideal gas, what is Quc? P2 [ Qab = 150 [J] (into the system) Qbe = 66 [J] (out of the system) Pi = 14 x 10" (Pa] 2 = 20 x 10* (Pa] V = 3 x 10-3 (m] V2 = 11 x 10-3 (n"] A. 60 (J) В. 352 (J) С. 136 [J] D. 216 (J]
Chapter2: The Kinetic Theory Of Gases
Section: Chapter Questions
Problem 34P: (a) What is the gauge pressure in a 25.0 cc car tire containing 3.60 mol of gas in a 30.0-L volume?...
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