P2 657°C Isothermal 2.0 37°C atm 3. V(L) V3 The figure (not to scale) shows a pV diagram for 3.3 g of helium gas (He) that undergoes the process 1→ 2 → 3. The ideal gas constant is R = 8.314 J/mol · K = 0.0821 L· atm/mol · K, and the atomic weight of helium is 4.0 g/mol. What is the %3D value of V3 in liters? Please give your numerical answer with one decimal place.
P2 657°C Isothermal 2.0 37°C atm 3. V(L) V3 The figure (not to scale) shows a pV diagram for 3.3 g of helium gas (He) that undergoes the process 1→ 2 → 3. The ideal gas constant is R = 8.314 J/mol · K = 0.0821 L· atm/mol · K, and the atomic weight of helium is 4.0 g/mol. What is the %3D value of V3 in liters? Please give your numerical answer with one decimal place.
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter19: Temperature, Thermal Expansion And Gas Laws
Section: Chapter Questions
Problem 61PQ
Related questions
Question
![P2
657°C
Isothermal
2.0
atm
37°C
3.
V(L)
V3
The figure (not to scale) shows a pV diagram for 3.3 g of helium gas (He) that
undergoes the process 1 2 → 3. The ideal gas constant is R = 8.314 J/mol K =
0.0821 L· atm/mol K, and the atomic weight of helium is 4.0 g/mol. What is the
%3D
value of V3 in liters?
Please give your numerical answer with one decimal place.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa9e17fc7-257f-41bb-9723-f7b4756fe882%2Fb2f2335e-b2b5-433b-8242-d72217695cc8%2F10gymro_processed.jpeg&w=3840&q=75)
Transcribed Image Text:P2
657°C
Isothermal
2.0
atm
37°C
3.
V(L)
V3
The figure (not to scale) shows a pV diagram for 3.3 g of helium gas (He) that
undergoes the process 1 2 → 3. The ideal gas constant is R = 8.314 J/mol K =
0.0821 L· atm/mol K, and the atomic weight of helium is 4.0 g/mol. What is the
%3D
value of V3 in liters?
Please give your numerical answer with one decimal place.
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