Of the statements provided, which one is true for Hardy-Weinberg Equilibrium (HWE)? The population is evolving due to genetic drift. O Natural Selection is not occuring within the population. Op+q=1 calculates genotype frequencies. O Individuals within the population move back and forth between another nearby population.

Of the statements provided, which one is true for Hardy-Weinberg Equilibrium (HWE)? The population is evolving due to genetic drift. O Natural Selection is not occuring within the population. Op+q=1 calculates genotype frequencies. O Individuals within the population move back and forth between another nearby population.

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter19: Population Genetics And Human Evolution

Section: Chapter Questions

Problem 2QP: How Can We Measure Allele Frequencies in Populations? The MN blood group is a single-gene,...

See similar textbooks

Similar questions

Under idealized Hardy-Weinberg conditions, which of the following is FALSE? [1] O mutation rates will increase with each generation O no new alleles would be added to the population's gene pool O there will be no change in alelle frequencies in a population over time O the population is so large that random affects don't change allele frequencies all of these are true
On the off chance that gene A/an isn't in Hardy-Weinberg equilibrium because of natural selection to such an extent that people with the genotype AA have a fitness of 1.0, heterozygotes have just marginally decreased fitness at 0.9, and people with the genotype aa have a fitness estimation of 0.6, what sort of progress in allele recurrence/frequency would you hope to see over the long haul accepting you start with equivalent frequencies of the 2 alleles?
Hitchhiker's thumb is an autosomal recessive trait determined by a single gene with two alleles, H and h. Suppose the allele frequencies in a population are f(H) = 0.8 and f(h) = 0.2. Which combination(s) of genotype frequencies is/are possible in this population if it is in Hardy- Weinberg equilibrium? List all that are possible. O f(HH) = 0.64, f(Hh) = 0.32, f(hh) = 0.04 O f(HH) = 0.6, f(Hh) = 0.2, f(hh) = 0.2 %3D f(HH) = 0.6, f(Hh) = 0.4, f(hh) = 0 %3D f(HH) = 0.7, f(Hh) = 0.2, f(hh) = 0.1 O f(HH) = 0.8, f(Hh) = 0, f(hh) = 0.2
An allele A is present in a population at a frequency of 0.29, and there is only one other allele at the same locus. Fitness is associated with variation at the locus carrying the A allele such that there is a selection coefficient s equal to 0.03. What would you expect the frequency of the A allele to be after one generation of natural selection. Compute your result up to four decimal places.
Which of these statements is true for a highly inbred population, if there are no other violations of Hardy-Weinberg equilibrium? O Frequency of homozygous individuals increases, yet frequency of alleles does not change. O None of the above are true. O Frequency of heterozygotes increases, and frequency of alleles changes. O Frequency of homozygous individuals decreases, yet frequency of alleles does not change.
What is the intuitive meaning of the mean fitness of a population? How does its value change in response to natural selection?
A species of insect has a gene that determines whether the legs have brown stripes or black stripes, with brown being completely dominant over black. There are 76 BB insects, 50 bb insects and 124 Bb insects. If there were 90 brown individuals and 15 black individuals in the parent population, what can be concluded about the population? * O The population is not evolving. O The population is evolving. Stabilizing selection is occurring. O The population is in Hardy-Weinberg equilibrium.
How Can We Measure Allele Frequencies in Populations? The MN blood group is a single-gene, two-allele system in which each allele is codominant. Why are such codominant alleles ideal for studies of allele frequencies in a population?
How Can We Measure Allele Frequencies in Populations? Drawing on your newly acquired understanding of the HardyWeinberg equilibrium law, point out why the following statement is erroneous: Because most of the people in Sweden have blond hair and blue eyes, the genes for blond hair and blue eyes must be dominant in that population.
The relative fitnesses of A,A1. A,Az and A2A2 are 0.5. 0.8, and 1 respectively. What is the expected result of natural selection in this situation? A, will increase and A2will decrease. O A2 will increase and A, will decrease. Both alleles will decrease in frequency. A stable equilibrium will be achieved in which both alleles are maintained. An unstable equilibrium will exist and the outcome depends on the allele frequencies.
The evolution of a qualitative trait in reponse to natural selection is described by the following equation, R=h2 S a) What is S and what does it measure? b) Describe a study that woukd allow you to estimate S in a real population.
Your study of the natural hamster population yields observed genotypic frequencies of 60% AA, 20% Aa and 20% aa. Compare the observed genotypic frequencies with the expected frequencies for a population in Hardy-Weinberg equilibrium. Genotype Observed Expected AA 0.60 0.30 Aa 0.20 0.50 aa 0.20 0.20 Is this population in Hardy-Weinberg equilibrium? Is it likely this population is experiencing evolution as defined by changes in allele frequencies between generations?