m h A block of mass m sliding down an incline at constant speed is initially at a height above the ground, as shown in the figure. The coefficient of friction between the mass and the incline is k. If the mass continues to slide down the incline at a constant speed, how much energy is dissipated by the friction by the time the mass reached the bottom of the incline? mgh/k kmgh/cos(Theta) kmgh/sin(Theta) mgh
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- A differential equation encountered in the vibration of beams is d4ydx4=2D where x = distance measured along the beam; [x]=[L] y = displacement of the beam; [y]=[L] = circular frequency of vibration; []=[T1] = mass of the beam per unit length; []=[ML1] D = bending rigidity of beam; [D]=[FL2] Show that the equation is dimensionally homogeneous. Note that [F]=[MLT2] see Eq. (1.21:).Consider the system shown below. Block A weighs 95.0N and block B weighs55.0N. Once block B is set to downward motion, it descends at a constant speed.A) Calculate the coefficient of kinetic friction between block A and the tabletop.B) A dog, also of weight 95.0N, Falls asleep on top of block A. If block B is now setinto downward motion, what is its acceleration (magnitude and direction)?A block is pulled along a rough level surface at constant speed by the force P. The figure shows the free-body diagram for the block. FN represents the normal force on the block; and / represents the frictional force. If the coefficient of kinetic friction, HR , between the block and the surface is 0.30 and the magnitude of the frictional force is 80.0 N, what is the magnitude of the normal force FN? mg OA 410 N OB 160 N OC 1.6 N OD.4.0 NA OE 270 N
- Hazel stands on the edge of a lookout admiring the view of a waterfall. The lookout is supported by a horizontal beam and a strut that makes an angle of 70° with the vertical. Hazel's mass is 60 kg 70° What is the horizontal force along the beam at the spot where she is standing? Use g = 9.81 m/s? for the acceleration due to gravity. Give your answer to the nearest Newton. Select one: a. 1721 N • b. 214 N c. 1617 N d. 626 NQ- A block of mass 100 kg is attached to springs of spring constant K₁ = 40 N/m and K₂ = 60 N/m. The block is displaced to the left through a distance of 2.5 m. The speed of the block when it passes through it's original position is _m/sec.pls send me answer of this question all the parts pls and i will rate you sure, pls solve a,b,c and d and also a and b A 200-kg dragster (racing car) exerts a constant force of 4000 N during a race. The coefficient of kinetic friction between the tires and the pavement is .15. If the drag strip is 1000 m long, determine:a. The net force on the dragster. b. The acceleration of the dragster. c. The time it takes for the dragster to finish the race.d. The dragster's velocity at the end of the race.The dragster now needs to slow down, so it opens a parachute. The force of air drag is 3500 N. The driver also locks the brakes of the dragster, and the coefficient of kinetic friction becomes .75. Determine:a. How long it will take to stop the dragster.b. The distance the dragster travels while stopping.
- |%EE l, I1. a T:0Y 1 aiymaatb5m تسجيل A Powetoint Presentation - Adobe acmbor Reader DC G2-bit) File Esit View Sign Window Help Home Tools PowerPrint Present. Sign In Example #4 : The coefficient of friction between the 20KN block A and the 40KN block B of Figure below is 0.40. The coefficient of friction berween block B and the horizontal plane is 0.15. Determine the force P required to cause motion of block A to impend to the right. SOLUTION : There are 2 case for this problem : Case 1 about the force P will cause motion of A to impend to the right alone without moving Block B Case 2 about the force P will cause motion of A to impend to the right with moving Block B with it in same time. تم انضمام علي عصام کاظم حميد إلى الاجتماع. ۳۷ مشارك آخر Salam عبد الوهاب أنتQs: Two blocks are connected by a string. Block 1 is on a frictionless surface, while block 2 hangs freely. The string passes over a massless frictionless pulley. Find the acceleration of block 1, if the acceleration of block 2 is equal to 3.8m/s², and the tension in the string. 2.2 Kg 1.4 Kg1. Consider the system shown below. Block A weighs 95.0N and block B weighs 55.0N. Once block B is set to downward motion, it descends at a constant speed. A) Calculate the coefficient of kinetic friction between block A and the tabletop. B) A dog, also of weight 95.0N, Falls asleep on top of block A. If block B is now set into downward motion, what is its acceleration (magnitude and direction)? A
- 1. 500 kg roller starts from a point A as shown in the diagram below. If throughout its travel the average retarding force due to air friction on the wheel is 200 N. What is its speed at points B and C given that |AB| = 100 m and |BC| = 50 m. How far will it travel at the | elevation of C before coming to rest? A 20 m 5 mThe motor exerts a constant force of T (N) on the cable. The final speed of the crate of mass m (kg) is v (m/s). Find the equatlon tidl will define the distance x (m) down the plane that the crate will move, starting from rest. The coefficient of kinetic friction between the plane and the crate is 0.3. The final state is at h = 0 m. 0 (degrees) is the angle between the plane and the horizontal. g = 9.81 m/s?. Crate Motor O !mv /(9.81 * m * sind +T - 0.3 * 9.81 * m * cos0) m O mv / (9.81 * m * sin0 +T+0.3 * 9.81 * m * cos0) m O mv /(-9.81 * m * sin0 – T + 0.3 * 9.81 * m * cos0) m O mv /(9.81 * m* cos0 + T – 0.3 * 9.81 * m* sind) m Clear my choiceA crate of 69 kg simply stands on the moving cart with constant acceleration a. The height from the center of gravity to the cart, L, is 1.4 m, and the angle = 13°. What is the maximum acceleration a (in m/s²) the cart can have without sliding on the cart? The coefficient of static friction between the crate and the cart is μl g = 0.51. Please pay attention: the numbers may change since they are randomized. Your answer must include 3 places after the decimal point. Take g = 9.81 m/s². 0.5 m 0.5 m L Your Answer: Answer G