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- Q2: A person of skin temp. of 30 K and body surface area 1.75 cm2, find: (a): net total power if he receives radioactive power from the surrounding walls 22 °C would be about 735 w. (6 = 5.7 x 10 12 w/cm) (b): The emissivity of surrounding walls. Good luckWe need to build a heatable warehouse with a capacity of 2000 cubic meters. Because the building is located in a milieu-valuable area, only a pitched roof building with a 45- degree roof slope is allowed to be built there (see the attached picture), other building shapes aren't permitted. However, the width (a), length (b) and ridge height (c) can be varied. a 45° b Since the warehouse owner is one of the local leaders of Global Green Turn, it is his firm wish that the warehouse energy (heat) loss should be as small as possible. According to the builder, the building's walls and roof have both exactly the same heat resistance, but there's no heat loss through the floor into the ground at all. Consequently - we have to design a warehouse with a volume of 2000 cubic meters with the smallest possible total area of all walls and roofs. Task: What should be the actual width (a), length (b) and roof ridge height (c) of such a building?2. Calculate Passive House's energy demand. a, Calculate window U-value based on given data in figure. 0.117m 0.117m 0.134m C₂ Utotal Wglass-0.996m = 1.229m glass Uglass = 0.6- glass W window - 123m W m².c 0.117m 1.48m nwindow W m² °C Uframe = 1.6- Area₁ U₁ + Area2 U₂... + Area, * U₁ Area total b. With the calculated U value for the windows find out how much power needed to maintain 20°C in a home with outside of 0°C based on the following: the house having a square footprint 17 m by 17 m, walls 2.5 m high (Uwalls = 0.152 each of the four walls hosting two windows, and each window having an area of 2 m². The entry door area is 2.5 m² (Udoor = 0.65- ). What are the heat loss rates for the installed windows, the door, the walls, the ceiling, and the floor? What is the overall heat loss rate of the home? m². C 1. What do these calculated heat loss rate values mean? 2. What is the definition of the passive house? 3. What does the U-value represent? Use its unit as a hint and describe it…
- 2b. List tools which can be used to for minutes ahead forecasting? Compare the geo-thermal technologies used at different 2c. temperaturesSome help please (How do I go about this? TIA)...Determine the rate of heat loss per square foot through thr wall of your home if the home is heated to 70F when the outside temperature of -10F. Assume the fiberglass insulation has the same properties as silica glass fiber.Please solve both parts with handwriting please need with correct answer need awesome answer solve both handwriting i requested to u. Part6. An exposed 8 cm external diameter, 20 m long hot-water pipe at 80°C is losing heat to the surrounding (outdoor) air by natural convection. The average outdoor temperature is 5°C. The heat transfer coefficient is 25 W/m2°C. What is the heat loss by natural convection, in kW? A. 9.4 W B. 10.0 W C. 10.4 W D. 11.4 W Part7. A spherical ball with a diameter of 10 cm has an outer surface that is maintained at a temperature of 200°C. It is suspended in the middle of a room that has an average temperature of 20°C. If the surface emissivity is 0.8, determine the rate of radiative heat transfer from the ball to the room in W. (Choose the nearest value) A. 2.3 W B. 4.5 W C. 19.4 W D. 60.8 W
- 1) "Two-by-four" wood studs have actual dimensions of 4. 13 x 9.21 cm and a thermal conductivity of 0.1 W/m. °C. A typical wall for a house is constructed as shown below. Calculate: a) heat transfer rate through the wall, b) temperature of inside wall, outside wall, and insulation material; and (c) temperature drop across common brick. Disregard any contact resistances at interfaces. Outside air convection, h = 15 W/m?. °C Common brick, k= 0.69 8 cm 1.9 cm, k = 0.96 Gypsum sheath 1.9 cm. k= 048 40.6 cm Insulation, k = 0.04 2 x 4 studs Inside air convection, h= 7.5 W/m²• CFor your company you need to mass produce 20-cmx10-cm heat sinks to dissipate heat quickly from an equipment. After considering several other parameters, you have short-listed two possible designs: A. 72 straight pin fins made of an alloy (thermal conductivity 240 W/m-°C) that costs $9,000 per m³. Each pin is 4 cm long and 1-cm diameter. E.=3'18; $204 B. 64 straight rectangular fins made of another alloy (thermal conductivity 180 W/m.°C) that costs $12,000 per m³. Each pin is 4 cm long and has 2-cmx1-cm cross-section. Eo =7:94%$ 6·14 The convection coefficient of the operating condition is approximated as 15 W/m2.°c. Consider that the manufacturing cost is same for both designs but the material cost differs. Calculate and compare the cost and performance (in terms of heat transfer gains by the heat sinks) of the two heat sinks so that a decision can be made to select a design.a. A slab of thermal insulator is 100 cm² in cross section and 2 cm thick. Its thermal conductivity is 2.4 x 10 -+ cal/(s cm C"). If the temperature difference between opposite faces is 180 F', how much heat flows through the slab in one day?
- Examples of external data I can use to support the claim that the consumers living within regions with hot climate will buy the stainless steel pan with digital thermometer reading that is powered by the heat generated while cooking and that sales will be higher in summer.The thermal conductivities of wood is kwood = 0.1W/(m°C)and air is kair = 0.0234W/(m°C). Part A If the temperature of the room is 20°C and outside is 10°C, find the rate of heat flow for a wall of wood with area = 10 m² and thickness of 5cm. O 60 W O 304 W O 34 W O 200 W O 100 W Submit Request Answer Part B The wall of wood with thickness of 5cm is now replaced with two layers of wood and a gap of air between the wood. Each layer of wood has a 2.5cm thickness and the gap is 1cm. The rate of heat flow will, decreases. increases. stay the same. Submit Request Answer Part C The temperature in the air gap will be, O 20°C, between 10°C and 20°C, O 10°C,The construction of PV solar cells uses a number of critical elements. One is indium, an ingredient of the transparent conducting coating on the surface of the cell. The average material intensity for indium in solar cells is approximately 0.05 kg/kWnom. Calculate the quantity of indium that would be required for a project that would provide PV solar power with capacity factor of 0.25, sufficient to meet one third of the present needs of the US, population 301 million, each using an average of 10.2 kW. The current world production of Indium is 600 tonnes per year. If the solar project were to be implemented over a 5 year time span, is it true that the supply of indium be adequate? True False