In a simple pendulum with no friction, a pendulum bob swings along the circular arc indicated in the figure below mechanical energy is conserved. As the pendulum swings from point A to point B, what is the energy at point B? Labeling goes from A to E, left to right. A. all gravitational potential energy B. gravitational potential energy = kinetic energy C. all kinetic energy D. 3/4 gravitational potential energy = 1/4 kinetic energy 3. Energy, in a closed, isolated system, is always changed from one form to another with a net loss or gain. A. True B. False

In a simple pendulum with no friction, a pendulum bob swings along the circular arc indicated in the figure below mechanical energy is conserved. As the pendulum swings from point A to point B, what is the energy at point B? Labeling goes from A to E, left to right. A. all gravitational potential energy B. gravitational potential energy = kinetic energy C. all kinetic energy D. 3/4 gravitational potential energy = 1/4 kinetic energy 3. Energy, in a closed, isolated system, is always changed from one form to another with a net loss or gain. A. True B. False

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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1) A small steel block and a magnet rest on a horizontal frictionless table. The steel block weighs 0.07N and the magnet is fixed to the table. The force acting on the steel block by the magnet is inversely proportional to the square of the distance between the steel block and the magnet. When the block is 26cm away from the magnet, the force becomes 0.145N. If the block starts its motion from rest at this position, what is the magnitude of the velocity of the block when it is 9.5cm away from the magnet?
F1 F2 a C F3 A B b F4 D E Consider the following values: - F5 a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 2 kN; F3 - a = 30° , 0 = 60°, B = 30° 5 kN; F4 = 7 kN; F5 = 3 kN; %3D 1] What is the resultant moment of the five forces acting on the rod about point A?
4. In an amusement park rocket ride, cars are suspended from 4.25-m cables attached to the rotating arms at a distance of 6.00 m from the axis of rotation. The cables swing out at an angle of 45.0° when the ride is operating. Consider the mass of a rocket car is 75 kg. 4.25 m 4.25 m 45.0°l !45.0° 6.00 m 6.00 m a) Find centripetal force on the rocket. b) What is the angular speed of rotation of the rocket? c) Find the radial and tangential acceleration of the rocket.
2. Two systems of forces are shown in the figure below. Are they equivalent? Show your entire cakulations. EE 100N 200 N 1.5m 1.5m 100 N 500 N.m 1.5m 1.5m 300 N.M 200N System 1 System 2
A:01 IE 0 & F1 F2 F3 b a F4 D E B FS Consider the following values: - a - 25 m; b - 5 m; a - 25 m; d - 5 m; F1 - 3 kN; F2 - 1 kN; F3 - 4 kN; F4 - 6 kN; F5 - 8 kN; a = 30°, 0 = 60°, B= 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 85.8 kN.m b) - 21.1 kN.m c) - 13.5 kN.m d) 7.9 kN.m e) 24.1 kN.m f) - 57.8 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 188.8 kN.m b) - 153.5 kN.m c) 111.6 kN.m d) - 98.9 kN.m e) 85.4 kN.m f)- 244.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 186 kN.m b) - 171 kN.m c) 155 kN.m d) 279 kN.m e) 423 KN.m 0 353 KN.m 4] What is the resultant moment of the five forces acting on the rod about point D? b) - 184.2 kN.m )-211.9 KN.m d) 126.9 kN.m e) - 27.1 KN.m ) 125.1 kN.m a) 117.8 kN.m Activate 5] What is the moment of the force F2 about point E? Go to Setting 1) 32.3 kN.m a) 11.7 KN.m b) 19.8 kN.m c) 54.6 kN.m d) 9.1 kN.m e) 41.1…
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F1 F2 a F3 F4 Consider the following values: - F5 a - 25 m; b -5 m; c 25 m; d 5 m; F1 - 3 kN; F2 - 1 kN; F3 4 kN; F4 - 6 KN; F5 - 8 kN; a = 30°, 0 = 60° , B 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 85.8 kN.m b) - 21.1 kN.m c) - 13.5 kN.m d) 7.9 kN.m e) 24.1 kN.m f)- 57.8 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 188.8 kN.m b) - 153.5 kN.m c) 111.6 kN.m d) - 98.9 kN.m e) 85.4 kN.m 1-244.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 186 kN.m b) - 171 kN.m c) 155 kN.m d) 279 kN.m e) 423 kN.m ) 353 kN.m DI
F1 F2 A F4 Consider the following values: - F5 a -7 m; b - 3 m; a -7 m; d - 3 m; F1 3 kN; F2 - 11 KN; F3 - 2 kN; F4 - 20 kN; F5 - 2 kN; a= 30°, e= 60°, B= 30° 1) What is the resultant moment of the five forces acting on the rod about point A? a) 90.8 KN.m m.220ט e) 14.6 KN.m d) 55.9 kN.m e) 21.6 kN.m H 61.3 KN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 77.8 KN.m b) 25.7 kN.m ) 38.6 kN.m d) 18.9 KN.m e) 37.9 KN.m ) 84.2 KN.m 3] What is the resultant moment of the five forces acting on the rod about point C? )35.7 kN.m b) 21.1 KN.m ) 714.6 kN.m d) 69.1 kN.m *) SL4 kN.m 0 85.3 N.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 17.8 KN.m b) 55.7 kN.m ) 44.6 kN.m d) 18.9 kN.m e) 21.5 kN.m 0 30.1 kN.m 5] What is the moment of the force F2 about point E? ) 64.6 kN.m a) 81.7 kN.m b) 78.1 kN.am d) 73.1 KN.m e) 54.6 kN.m H 61.3 kN.m
1. A bracket is subjected to four forces and a moment as shown in the figure below. Determine: (a) Magnitude and direction of the resultant force, (b) Point where line of action of resultant intersect member OA measured from O. 200 N 100 N 150 N 2 m 2m A 2 m 200 Nm 300 N 2 m
3. Two masses are attached to a uniform meter stick as shown in the figure below. The masses of m1 and m2 are as given and the meter stick weighs 150 g. A force f with unknown magnitude is applied on one end of the stick at an angle of 30° to balance the system. 30 сm 30 сm 40 cm 30° m1 50 g m2 75 g a) What is the magnitude of F? b) What are the reaction forces on the support?
D 3 m 2 m A 4 m B E AB F(AB)=Dtension force in AB АВ F = F(AD)=tension force in AD AD %3D F = F(AC)=tension force in AC AC Weight of the flowerpot is 40 Newton. W=weight of the flowerpot Express the tension force in AC as a vector form.
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