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- I am supposed to draw a shear force diagram and bending moment diagram for this frame. I found the exact same question and solution but it is the imperial version, not the SI version that I have so the numbers are different. Please draw the diagrams for this problem. I have done the question but I don't know if my answers are right after using the virtual work and force methods. Set Ax & Ay as redundants: Ex = 100kN ; Ey = 260kN ; ME = 445 kNm deltaAx = -1950/EI deltaAy = -2375/2EI fAx,Ax = 252/EI fAy,Ay = 125/3EI fAx,Ay = -75/EI Compatibility Equation: deltaAx + (fAx,Ax)(Ax) + (fAx,Ay)(Ay) = 0 deltaAy + (fAx,Ay)(Ax) + (fAy,Ay)(Ay) = 0 Ax = 34.94kN Ay = 91.38kN New reaction values: Ex = 65.06kN ; Ey = 168.62kN ; ME = 197.74kNmSolve for Problem 2, when RN1 = 0145topic: torsion in circular shafts The hollow shaft used in the system has the following conditions: Outer diameter (Ø): 150 mm Ø Allowable Shearing Stress: 85 MPa Determine the thickness (mm) of the shaft. Round to the nearest whole number for the thickness and use 2 decimal places for other solved values. Provide a torque diagram, strictly follow instructed sign convention, and start from left to right.
- An engineer wants to wind 10 turns of wire on a cylindrical rod. He/she measures the diameter of the rod to calculate using a micrometer to estimate the needed wire length. If the reading of the diameter is given in figure, calculate the required wire for 10 turns. di en aretle o 1 8 9 10 Least significant bit- 0.05 mm, and zero error is 0. (Hint: 1 = 3, the length of the cylindrical bar is enough, and the windings do not overlap) A. 91.1 mm wire B. 83.7 mm wire C. 52.1 mm wire D. 62.4 mm wire E. 56.3 mm wire400 mm Fr= 800 150mm C 600 N -Fa = 400 150mm Ft = Draw bending torsional moments, shear forces and normal force diagrams for the given gear shaft system.The figure below shows the components of normal forces, the value of radial force on the gear wheel due to a tangential force of 636 N is N, Take pressure angle as 14½°. ....... af PN Pitch Pt point Gear driven 02 The radial force is
- Q-3 Three blocks A, B, and C and a grooved block D have dimensions a, b, c, and d as follows: a = 40.500 0.025 mm b = 52.000 0.075 mm c = 73.000 0.015 mm d = 165.900 0.250 mm Parts A, B, and C are standard parts supplied by vendors from the market, but we are to machine part D according to the the width that you are asked to specify. (a) Determine the mean gap w0 of w and its tolerance. (b) Determine the mean size of d (d0) that will assure that w ≥ 0.050 mm.Solve the problem. A 11-in. connecting rod in an engine connects the wrist pin of a piston at point A to the end of a second rod at point on the crankshaft. As the piston moves forward and back, the crankshaft is turned counterclockwise around point C. The stroke length of the engine is the distance that the piston travels (one way) with its cylinder. If the stroke length is 4 in., and the engine turns at 600 rpm, write a model representing the distance d (in inches) from A to the center of the crankshaft Cas a function of time t (in minutes). Assume that at t = 0, the piston is at its farthest point from the crankshaft. B B C C B A A stroke length8. First calculate the virtual conditions and resultant conditions for the pin and hole in the figure below (figure on the following page). Then calculate the maximum and minimum distances for dimensions X and Y. a. The Virtual Condition of the PIN: VCp = MMC + Geo. Tol. = b. The Virtual Condition of the HOLE: VCh = MMC-Geo. Tol. = c. Resultant Condition of the PIN: RCP = LMC-Geo. Tol. - Bonus =_ d. Resultant Condition of the HOLE: RCh = LMC + Geo. Tol. + Bonus = e. The maximum distance for dimension X: XMax = Dist. - RCp/2 - VCh/2 = f. The minimum distance for dimension X: XMin = Dist. VCp /2 - RCh /2 = g. The maximum distance for dimension Y: YMax =Dist. @ MMC - Basic Dimension - VCh/2 = h. The minimum distance for dimension Y: YMin = Dist. @ LMC - Basic Dimension - RCh/2 =
- Consider the s single degree of freedom presented in the figure Тol Base Knowing the position of the tool and using the inverse kinematics, find the angles on the joints of the robot. (Px=0.6, Py= 0.8, L=1) Select one: a. 0.9273 b. 36.87 c. 55.13 d. 0.6435Calculation 1. Define torque. 2. Give the expression for torque. 3. Define modulus of rigidity. 4- Investigate the relationship between the torsional moment, clamping length and torsional angle of a shaft. 5-Determine the shear modulus of steel, brass, and aluminium. 6-Give the values of G for different materials. 7-Graph Torque Vs Angle of TwistThe figure below shows the components of normal forces, the value of radial force on the gear wheel due to a tangential force of 642 N is . N, Take pressure angle as 140. PN Pitch point Gear driven 02 The radial force is