How many grams of BaCl2 needed to completely precipitate sulfate as BaSO4, knowing that 0.4758 g of BaSO4 is precipitated from 10.0 ml. of sulfate solution. (molar masses of BaSO-233 g/mol, BaCl-208 g/mol) 0.7818g 0.6926g 6033 g 5140 g 4247g

How many grams of BaCl2 needed to completely precipitate sulfate as BaSO4, knowing that 0.4758 g of BaSO4 is precipitated from 10.0 ml. of sulfate solution. (molar masses of BaSO-233 g/mol, BaCl-208 g/mol) 0.7818g 0.6926g 6033 g 5140 g 4247g

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter15: Complex Ion And Precipitation Equilibria

Section: Chapter Questions

Problem 70QAP

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

11:34 AM Fri 2 Sep
< Analytical Chemistry Lab
Q2
:
How many grams of BaCl2 needed to completely
precipitate sulfate as BaSO4, knowing that 0.4758 g of
BaSO4 is precipitated from 10.0 ml. of sulfate solution.
(molar masses of BaSO-233 g/mol, BaCl-208 g/mol)
0.7818g
0.6926g
6033 g
5140 g
4247g
SO4 BaCl₂ to Be
504
+3
nol:i:ill #md Ball₂ = #m²
70%
ASO4

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