For the dual oscilloscope displays shown in the figure with H, of 500 µs/div and V of 20 mV/div find (a) their frequency, (b) Vp-p value of V₁ and V₂ (c) their r.m.s. values, (d) their phase difference, and (e) their instantaneous voltage v₁ and v₂ equations
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- A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted between the plates without changing the spacing, and the capacitance becomes 15 F. What is the dielectric constant of this material?An RC series circuit is connected to a 120-V, 60-Hz power source. The resistor is 25 and has a voltage drop of 65 volts. What is the capacitance of the capacitor?A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?
- A double beam oscilloscope displays 2 sine waveforms A and B. The time/cm switch is on 150µs/cm and the volt/cm switch on 5 V/cm. The width of each complete cycle is 8 cm for both the waveforms. The height of waveforms A and B are 5 cm and 4 cm respectively. Determine their a) frequency, b) phase difference, and c) peak and d) r.m.s value of voltages. The difference between the two waveforms is 0.7 cm.A double beam oscilloscope displays 2sine waveforms A and B. The time/cm switch is on 100us/cm and the volt/cm switch on 2V/cm. The width of each complete cycle is 5cm for both the waveforms. The height of waveforms A and B are 2cm and 2.5cm respectively. Determine their a) frequency, b) phase difference, and c) peak and r.m.s value of voltages. The difference between the two waveforms is 0.5 cm.The main purpose of an oscilloscope is to graph an electrical signal as it varies over time. Most scopes produce a two-dimensional graph with time on the x-axis and voltage on the y-axis. The voltage waveform on the screen looks as shown in the figure below. Here, the vertical resolution of the oscilloscope is set up to be 2 mV/division and the horizontal resolution is 2 ms/division. Time 1. Determine the peak-to-peak amplitude of the wave. Voltage
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- The waveform displayed on an oscilloscope is as shown in Figure The 'time/cm' switch is set to 1 ms/cm, and the 'volts/cm' switch is set to 1 V/cm. Determine the (i) amplitude of waveform Q, (ii) peak to peak value of waveform P, (iii) frequency of waveform P and (iv) phase angle difference between P and Q in Degrees. P Upload your Answers steps in the "Final Answer Submission" Link provided in the Moodle. (i) Amplitude of waveform Q = (ii) Peak to peak value of waveform P = (iii) Frequency of waveform P = (iv) Phase angle difference between P and Q in Degrees =AC Circuits Sine-wave generator f- 25 kHz V₁ = 3.0 V VR 888 100 mH Figure 6-Test Circuit 3. Using a two-channel oscilloscope, measure the peak-to-peak voltage VR across the resistor and the peak-to-peak voltage VL across the inductor. Measure the voltage across the inductor using the difference technique described in a previous experiment. Record the voltage readings in Table 2. VL 10 k 1 XL Table 2- Measured and Calculated Values (f = 25 kHz) ZTThe time/div and voltage/div axes of an oscilloscope have been erased. A student connects a 1 kHz, 5 V P-P square wave calibration pulse to channel-1 of the scope and observes the screen to be as shown in the upper trace of the figure. An unknown signal is connected to channel-2 (lower trace) of the scope. If the time/div and V/div on both channels are the same, the amplitude (p - p) and period of the unknown signal are respectively