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From the spectral data that was given, identify the structure of the ester product. The mass is 116 amu and the molecular formula is C6H12O2. Based on your answer what is the structure of the starting alcohol?
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- NO(g) NO;(g) 90.25 210.7 86.57 33.2 240.0 51.30 N,O(g) N;O,(g) 82.05 219.7 104.2 83.72 321.28 139.46 (S)*O°N_ (3)*O°N 9.16 304.2 97.82 11 356 115 N,O;(s) -43.1 178 114 NOCI(g) HNO,(€) HNO,(g) 52.59 264 66,36 -174.1 155.6 -80.79 -135.1 266.2 -74.77 HNO, (aq) -206.6 146 -110.5 Hydrogen H(g) 218.0 114.6 203.3 H;(g) 130.6 H,O(€) -285.8 69.91 -237.2 H,O(g) -241.8 188.7 -228.6 H;O;() -187.8 109.6 -120.4 Cbromium Cr(s) 23.8 Cr,O;(s) Cr,Cl;(s) -1139.7 81.2 - 1058.1 -556.5 123.0 -486.1 (NH,) ¿Cr,O;(s) -1807 A -299.9 kJ/mol В 3,913.9 kJ/mol 299.9 kJ/mol D -3,913.9 kJ/molY. Temperature, K 303 K Time, min 44. Identify the region/s where solid NOOK can be observed. W/A chemist fills a reaction vessel with 3.61 atm nitrogen (N,) gas, 8.64 atm oxygen (0,) gas, and 6.55 atm nitrogen monoxide (NO) gas at a temperature of 25.0° C. Under these conditions, calculate the reaction free energy AG for the following chemical reaction: N,(g) + O,(g) = 2NO (g) Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule. do Data HNO3 (1) -174.1 HNO3 (g) -133.9 Oxygen OH (aq) H20 (1) -285.8 H20 (g) -241.8 02 (9) H202 (1) -187.8 H202 (9) -136.3 Phosphorus Explanation Check P4 (s) 2021 McC
- 1). The susceptibility of FeCl₂ obeys the Curie-Weiss law over the temperature range 90 K to room temperature (293K), with 0 =48K. Its molecular susceptibility at room temperature is 1.475 1022 emu/Oe g mol). (Use: N= 6.022 x 1023 atoms/g-mol, KB= 1.38 × 10-¹6 erg/K) (a) Show that the effective magnetic moment is 5.4 µB. (b) Show that the value of J is 2.25. (c) At an applied field of 8000 Oe, what is the value of the molecular field at 0 °C ?Determine the gravimetric factor of CrO4 in K₂Cr2O7. The atomic weight of chromium is 52g/mol 0.7891 0.3946 0.8791 0.4936 оSi crystalizes into a diamond crystal structure with lattice constant a = 0.543\: nma=0.543nm. Calculate the atomic density in units of cm^{-3}cm−3. Values within 5% error will be considered correct.