E, = bx? Let the distribution of electric field strength in a certain area of space be y E, = E. = 0 and b = 800N / (C-m ²) Please find the electric field intensity flux through the cube as shown, The side length of the cube is : a = 10 cm, The distance between one of its sides and the Oyz plane is "a" , And find the total charge in the spherical cube. У a a
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- The surface charge density on a long straight metallic pipe is . What is the electric field outside and inside the pipe? Assume the pipe has a diameter of 2a.Two parallel conducting plates, each of cross-sectional area 400 cm2, are 2.0 cm apart and uncharged. If 1.01012 electrons are transferred from one plate to the other, what are (a) the charge density on each plate? (b) The electric field between the plates?1 ! 7 A skát с A spherically symmetric charge distribution produces the electric field E=( 5400 r²) N/C, where r is in m. Z mylabmastering.pearson.com/?courseld=12649908&key=55673220682936520262024#/ 2 pos W S X 3 20 F3 E D $ 4 C 888 R F What is the electric field strength at r= 16.0 cm ? Express your answer in newtons per coulomb. VG ΑΣΦ 4 Submit Part B Submit Part C What is the electric flux through a 32.0-cm-diameter spherical surface that is concentric with the charge distribution? Express your answer in newton meters squared per coulomb. ΕΠΙ ΑΣΦ % [VG| ΑΣΦ 5 Request Answer V FO Request Answer T How much charge is inside this 32.0-cm-diameter spherical surface? Express your answer in coulombs. G 4 a ^ 6 C 244 MacBook Air Y B SMC & ? 7 H ? N/C 80 F7 N-m²/C U C N H 8 - DII FS 1 ( 9 M DD K chegg.com X C ☆ O O MOSISO O 4 P
- The volume charge density of a spherically charged cloud changes with the distance to the cloud center as p(r) = po r a " where the parameters are po 1.85 nC/m³ and a = 22 m. Find the magnitude of electric field at distance d = 25 m from the cloud center. The electric field, E(r = 25 m) = 1484.65 Find the electric field (in N/C) as a function of r (in m). Do not submit the units. The electric field, E(r) = 1484.65 N/C. = Units N/CThe volumetric charge density of a cylinder of radius R is proportional to the distance to the center of the cylinder, that is, ρ = Ar when r≤R, with A being a constant. (a) Sketch the charge density for the region - 3R < r < 3R. What is the dimension of A?b) Calculate the electric field for a point outside the cylinder, r > Rc) Calculate the electric field for a point inside the cylinder, r<R.d) Sketch ExrA closed surface with dimensions a = b 0.272 m and c = the figure. The electric field throughout the region is nonuniform and defined by E (a+ Br)î where r is in meters, a = 3 N/C, and 3 = 5 N/(C -m²). 0.4896 m is located as in E What is the magnitude of the net charge enclosed by the surface? Answer in units of C. A. to sh What is the sign of the charge enclosed in the surface? R 1. Cannot be determined 2. Negative 3. PositiveThe volume charge density ρ for a spherical charge distribution of radius R= 6.00 mm is not uniform. (Figure 1) shows ρ as a function of the distance r from the center of the distribution. a)Calculate the electric field at r = 1.00 mm. b)Calculate the electric field at r = 1.00 mm.A solid insulating sphere of radius R has a volume charge density p given by p= pexp(-r/a"), where po.a >0 are both constants and r is the distance from the center of the insulator. Which of the following gives the correct expression for the electric fiekd magnitude at a distancer< R inside the insulator? A. E- exp В. Е exp fo 3 c. E = - (-)} D. E = - e(-)} exp E. E= 1-expA spherical shell with uniform volume charge density ρ = 1.84 nC/m3, inner radius a =10.0 cm, and outer radius b = 2.00a (Figure 5). What is the magnitude of the electricfield at radial distancesi. r = 0 ii. r = a/2.00 iii. r = a iv. r = 1.50a v. r = b vi. r = 3.00bThe electric field that comes out perpendicularly from the surface of the circular crown of internal radii a=10 www um www wwwwwwwww wwwwwwwwww cm, external b=20 cm, depends on the radial distance "r", according to: www E=E.(r/rm)² Where Eo=500 N/C is a constant and "rm" is the mean radius of the crown. Find the electric flux (in Nom²/c²) passing through the surface of the crown. a) 50,4 b) 51,4 a 0 E c) 52,4 b d) 53,4 e) 54,4a) Find the surface charge density σ2 of the cylindrical shell of radius R2. (Note the unit in the input box and the sign of charges.) Surface charge density σ2Give your answer up to at least three significance digits. b) Find an expression of electric field at rmm from the center where R1<r<R2. Assume the cylinder has a length L and L is very long so that electric field is uniform. Consider that the insulating material between the cylinders is air. (Hint : use Gauss's law and cylindrical Gaussian surface with radius r.) Magnitude of the electric field at r=0.76mm Give your answer up to at least three significance digits. c) Calculate absolute value of the potential difference between the wire and the cylinder. Absolute value of the potential difference Give your answer up to at least three significance digits. d) Calculate the capacitance C for this cylindrical system. Assume that the length of the cylinder is L=17cm. Capacitance C for this cylindrical system Give your…SEE MORE QUESTIONS