Answered: An electric field of intensity 3.50…

An electric field of intensity 3.50 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the plane is parallel to the xy-plane.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.63CP: A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure...

See similar textbooks

Related questions

Q: A cylinder is placed with its long side parallel to the electric fields from a vertical circle. The…

A: Here, a figure is given, showing a cylinder. Magnitude of electric field =60 N/C Radius of flat ends…

Q: Consider a plane surface in a uniform electric field as in the Figure , where d=15 cm and Theta=70…

A: Given Data : The net flux through the surface is given as ϕ=6 N.m2C. The angle of the electric field…

Q: Find the electric flux through a rectangular area 3 cm × 2 cm between two parallel plates where…

Q: An electric field of intensity 3.50 kN/C is applied along the x-axis. Calculate the electric flux…

A: Given, Electric field,E=3.5 kN/C=3500 N/C Dimensions of plane,A=0.35×0.7=0.245 m2 Angle between area…

Q: Calculate the electric flux for each of the closed surfaces a, b, c- d. b. 92 93 97 94 95

A: The electric flux is the ratio of the charge enclosed within the surface and permittivity of free…

Q: Consider a closed triangular prism box with height = h and base = 2a resting within a uniform…

Q: Calculate the electric flux for each of the closed surfaces a, b, c, and d. d. 92 93 97 94 95 98 96…

A: From Gauss's law, the electric flux through a closed surface can be given by, φ=qencε0, where qenc…

Q: In a symmetrical electric field of 58.3 x 101 N/C , a flat circle with a diameter of 30 cm is…

A: Given data: Electric field (E) = 58.3×101 N/C Diameter of the circle (d) = 30 cm = 0.30 m Circle's…

Q: A rectangular surface of sides 10cm and 25cm is placed inside a uniform electric field of 25V/m,…

A: Given data: Sides of rectangular surface: 10 cm and 15 cm Electric field (E) = 25 V/m Angle between…

Q: An electric field (E=4.5N/C) passes through a flat surface area (0.30 m) with an angle of 45°. What…

A: Given:- E = 4.5N/C flat surface area = 0.30 m angle θ = 45o . electric flux = E * S * cos θ N M2 C-1…

Q: There is an electric flux of 38.5 N⋅m^2/C through the square region shown in the figure. Each side…

A: Electric flux through a surface is given by- ϕE=∫E→.dA→=EAcos(θ) where,θ is angle between the…

Q: Calculate the electric flux passes through the object. A= (Πr2) E= 100 N/C R= 150 cm Φ = 40̊

A: Given data: A= (Πr2)E= 100 N/CR= 150 cmΦ = 40̊ Need to determine the electric flux passes through…

Q: A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The…

Q: An electric field of intensity 4.05 kN/C is applied along the x-axis. Calculate the electric flux…

Q: what can you conclude about the relationship among the electric flux, electric field lines, and the…

A: According to Gauss' Law the electric flux through closed surface is equal to the ratio of charge…

Q: 30 cm E 60° 10 cm Consider a closed triangular box resting within a horizontal electric field of…

A: The given values are,

Q: An electric field Ē = axî + By txzk exists, in space where.a, B.Y are constant. Electric flux…

Q: An electric field with a magnitude of 3.50 kN/C is applied along the x-axis. Calculate the electric…

A: Electric Flux is the measure of the electric field through a given area. The component of the field…

Q: The electric flux through an arbitrary closed surafce is ϕ=52Nm2/C. What is the charge enclosed by…

Q: A disk which has an area of 0.08 square meters and is tilted at an angle of 75 degrees with respect…

Q: A closed surface with dimensions a=b=D0.40 m and c=0.60 m is located as in the figure below. The…

Q: An electric field (E=4.5N/C) passes through a flat surface area (0.30 m) with an angle of 45˚. What…

A: The electric flux is the number of electric field lines crossing through a given area. The electric…

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm \( \times…

A: Given: The electric field is E=720.4 N/C. The angle is θ=30°. The area is A=30 cm×40 cm. The…

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.80 x…

Q: An insulating spherical shell of inner radius a and outer radius 4a, carries a frozen-in…

A: The electric field is a vector quantity thus it has both magnitude and direction to it. This field…

Q: A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is…

Q: A circular plane whose r=2.2m is placed in an electric field E=800N/C. The electric field makes an…

A: Answer:- Answer (1) Given Electric field (E) = 800 N/C Radius of a circular plane (r) = 2.2 m…

Q: A closed surface with dimensions a=b=0.40 m and c=0.60 m is located as in the figure below. The left…

A: Electric field at x = a = 0.4 m is Ea = (3 + 38 (0.4)2 ) = 9.08 N/C towards x - direction Electric…

Q: An electric field of intensity 3.50 kN/C is applied along the x-axis. Calculate the electric flux…

A: Given data: Electric field intensity along x – axis,Ex=3.50 kN/C = 3.50×103 N/C Length of the…

Q: A flat surface with an area of 1.25 m² is rotated through a uniform horizontal electric field of 5…

Q: An electric field of intensity 3.50 kN/C is applied along the x-axis. Calculate the electric flux…

A: Given data E=3500 N/C

Q: A 3.65x1012 Cis placed inside a cube. What is the amount of electric flux passing through each side?…

Q: An electric field of intensity 3.50 kN/C is applied along the x-axis. Calculate the electric flux…

Q: In free space, let D = 8xyz4ax + 4x2z4ay + 16x2yz3 az pC/m2. Find the total electric flux passing…

A: Electric flux is the rate of flow of the electric field through a dive area. ψ=∮D.ds .

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.86 ×…

Q: A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The…

A: Given : E=(3+57x2)i N/C a=b=0.40 m c=0.60 m We have to fins the net flux leaving the closed surface.

Q: Is the net flux through the Gaussian surface positive, negative, or zero?

A: Consider the electric field through the surface A is EA EA = k[(Q/rA+2 ) +(-Q/rA- 2 )] k= 1/(4πεo)…

Q: What is the total flux passing through a 10 cm × 6 cm surface in a region where the electric flux…

A: Electric flux is defined as the product of the electric field and the specified area. Electric flux…

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.02 ×…

A: (given) Electric field (E) in magnitude = 7.02 ×104 N/C (a) Electric flux through the vertical…

Q: A uniform electric field of strength E = 334 N/C passes through a flat surface at an angle of 0.880…

A: To find the area of the surface in given conditions. We are given with E=334 N/C angle θ=0.880…

Q: A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is…

A: Given in question - length (L) = 0.600 m Width(B) = 0.400m…

Q: In a symmetrical electric field of 58.3 x 10 , a flat circle with a diameter of 30 cm is positioned.…

A: Calculate the area of the circle. A=πD22=π30 cm×10-2 m1 cm22=0.0706 m2 Here, A is the area of the…

Q: The rectangular surface in the figure below is in a uniform electric field region with strength of…

Q: A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The…

Q: A right triangular prism is placed in a E = 200 N/C uniform electric field as shown in the Figure…

A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

Q: A right conical frustrum is placed in a uniform electric field that is parallel to the y axis, as…

A: Since the electric field is uniform so then net electric flux going in is the amount of electric…

Q: The electric field in the region of space shown is given by: E = (5i + 2j+6k) N/C, What is the…

A: Given : The electric field is E=5i+2j+6k NC. The edge length is L=6 m. The expression for electric…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

100%

An electric field of intensity 3.50 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the plane is parallel to the xy-plane.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure 124.63. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non- uniform and is given by E = (3.00 + 2.00x2)i N/C, where x is in meters. (a) Calculate the net electric flux leaving the closed surface. (b) What net charge enclosed by the surface?
a butterfly net is in a uniform electric field of magnitude E= 7mV/m. The rim of the net is a circle of radius a=1cm. If the rim is aligned perpendicularly with respect to the electric field, calculate the net electric flux through the netting in μNm^2/C^2
A 3.2-cm-diameter circle lies in the yz-plane with unit vector n^ pointing in the +x-direction. What is the electric flux through the circle if the electric field is E =(2500i^−1500j^+4000k^)N/C?
A uniform electric field of magnitude 3.6×104N/C is at an angle of 80° to a square sheet with sides 8.5 m long. What is the electric flux through the sheet?
A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is immersed in a uniform electric field of magnitude 95.0 N/C that is directed at 200 from the plane of the sheet. Find the magnitude of the electric flux through the sheet.
A circular surface with a radius of 0.066 m is exposed to a uniform electric field of magnitude 1.90 × 104 N/C. The electric flux through the surface is 52 N·m2/C. What is the angle between the direction of the electric field and the normal to the surface?
An electric field 7 N/C is passing through a region of area 2.1 m² in the xy-plane. If the electric field makes an angle of 56° with respect to the area vector perpendicular to the region, calculate the electric flux magnitude (in N-m²/C) through the region.
A uniform electric field E = 5000 N/C is passing through a flat square area A= 2m2 . Determine the electric flux. θ = 60o (the angle between the electric field direction and a line drawn perpendicular to the area)
An electric field of magnitude 2.82 kN/C is applied along the x axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true. (a) The plane is parallel to the yz plane. N-m²/c (b) The plane is parallel to the xy plane. N-m²/c (c) The plane contains the y axis, and its normal makes an angle of 35.0° with the x axis. N-m²/c
An electric field of magnitude 2.86 kN/C is applied along the x axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true. (a) The plane is parallel to the yz plane. N.m?/c (b) The plane is parallel to the xy plane. N- m2/c (c) The plane contains the y axis, and its normal makes an angle of 36.2° with the x axis. N. m?/c
A 3.7 cm × 4.0 cm rectangle lies in the xy-plane. What is the electric flux through the rectangle if E (vector) =(120ı^−240k^)N/C? What is the electric flux through the rectangle if E (vector) =(120ı^−240ȷ^)N/C?
The electric field that comes out perpendicularly from the surface of the circular crown of internal radii a=10 www um www wwwwwwwww wwwwwwwwww cm, external b=20 cm, depends on the radial distance "r", according to: www E=E.(r/rm)² Where Eo=500 N/C is a constant and "rm" is the mean radius of the crown. Find the electric flux (in Nom²/c²) passing through the surface of the crown. a) 50,4 b) 51,4 a 0 E c) 52,4 b d) 53,4 e) 54,4