Determine whether each statement is true or false. If a statement is true, give a reason or cite an appropriate statement from the text. If a statement is false, provide an example that shows the statement is not true in all cases or cite an appropriate statement from the text.(a) Geometrically, if λ is an eigenvalue of a matrix A and x is an eigenvector of A corresponding to λ, then multiplying x by A produces a vector λx parallel to x.(b) If A is an n × n matrix with an eigenvalue λ, then the set of all eigenvectors of λ is a subspace of Rn.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.9: Properties Of Determinants
Problem 24E
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Determine whether each statement is true or false. If a statement is true, give a reason or cite an appropriate statement from the text. If a statement is false, provide an example that shows the statement is not true in all cases or cite an appropriate statement from the text.
(a) Geometrically, if λ is an eigenvalue of a matrix A and x is an eigenvector of A corresponding to λ, then multiplying x by A produces a vector λx parallel to x.
(b) If A is an n × n matrix with an eigenvalue λ, then the set of all eigenvectors of λ is a subspace of Rn.

Expert Solution
Step 1

A set S is said to be a subspace of a vector space V if the following conditions hold:

1. The zero vector belongs to S.

2. If x, yS then, x+yS.

3. If xS and c is a scalar then, cxS.

We know that n is a vector space of n-tuples of the form x1, x2, x3, , xn where

the elements x1, x2, x3, , xn belong to the set of real numbers .

Step 2

Part a

We know that a number λ is said to be an eigenvalue of a matrix A if there is a non-zero vector x such

that Ax=λx.

It is given that λ is an eigenvalue of a matrix A and x is the corresponding eigenvector. Hence, Ax=λx.

We know that if we multiply a scalar c by a vector v then, the resulting vector cv is always parallel to the

vector v. Hence, λx is parallel to x.

Therefore, the given statement is correct.

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