Consider the integral , 3y - 4x 3 (3y - 4x) dA where R is the parallelogram bounded by the lines 3y - 4x = 0 R 19, y 5x = 0, and -y - 5x = - = - 19. = +2+ * -10 9 8 7 6 5 4 3 5 6 10 Compute the Jacobian corresponding to the change of variables u = 3y - 4x and v = The integral evaluates to I -y- 5x.

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