Consider the following complex ions: [NiBr6],[Ni(H2O)6]³* and [Ni(CO)6]³+. Using the Crystal Field Theory, in each case (i) draw d-orbital electron configurations (ii) determine the number of unpaired electrons (iii) predict the magnetic properties (iv) state and explain the complex is high-spin or low-spin.
Consider the following complex ions: [NiBr6],[Ni(H2O)6]³* and [Ni(CO)6]³+. Using the Crystal Field Theory, in each case (i) draw d-orbital electron configurations (ii) determine the number of unpaired electrons (iii) predict the magnetic properties (iv) state and explain the complex is high-spin or low-spin.
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter22: The Chemistry Of The Transistion Elements
Section22.6: Bonding In Coordination Compounds
Problem 22.5CYU
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Consider the following complex ions: [NiBr6]4-,[Ni(H2O)6]3+ and [Ni(CO)6]3+. Using the Crystal Field Theory, in each case
(i) draw d-orbital electron configurations
(ii) determine the number of unpaired electrons
(iii) predict the magnetic properties
(iv) state and explain the complex is high-spin or low-spin.
![Consider the following complex ions: [NiBr6],[Ni(H2O)6]³* and [Ni(CO)6]³+.
Using the Crystal Field Theory, in each case
(i)
draw d-orbital electron configurations
(ii)
determine the number of unpaired electrons
(iii)
predict the magnetic properties
(iv)
state and explain the complex is high-spin or low-spin.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6be5f8c7-22dd-488e-9e48-9eb50aad2ffa%2Fc04de7bb-8656-4110-a03c-efcedba04b72%2F7849cfd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the following complex ions: [NiBr6],[Ni(H2O)6]³* and [Ni(CO)6]³+.
Using the Crystal Field Theory, in each case
(i)
draw d-orbital electron configurations
(ii)
determine the number of unpaired electrons
(iii)
predict the magnetic properties
(iv)
state and explain the complex is high-spin or low-spin.
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