Add curved arrow(s) to draw step 2 of the mechanism. Modify the given drawing of the product as needed to show the intermediate that is formed in this step. Use the +/- tools to add/remove charges, and use the single bond tool to interconvert between double and single bonds. / + :Ö 1 H C N о P S F CI Br

Add curved arrow(s) to draw step 2 of the mechanism. Modify the given drawing of the product as needed to show the intermediate that is formed in this step. Use the +/- tools to add/remove charges, and use the single bond tool to interconvert between double and single bonds. / + :Ö 1 H C N о P S F CI Br

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter8: Addition Via Carbocation

Section: Chapter Questions

Problem 18CTQ: The reactants, intermediates, final products, and all curved arrows showing bonds forming...

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The first step of the mechanism is given in the sketch box below. Modify the given drawing of the product as needed to show the intermediate that is formed in this step (based on the provided curved arrows). Use the +/- tools to add/remove charges, and use the single bond tool to interconvert between double and single bonds. H₂C 2 P Edit Drawing H₂C
027 In Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 4 See Periodic Table O See Hint :0: :Br: Add the missing curved arrow notation. S CI Br Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Kea > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e., Keq« 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg 1) because bromide is a better leaving group than acetate. +
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