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- In a Direct Mapped Cache Memory Physical Address format the Cache line offset field size and word offset field size are same (with word size of one Byte). The number of tag bits in the Physical Address format is equal to the number of blocks in Cache Memory. If the Tag field Size is Mega words. 16 bits, the size of the physical Memory isThe length of the physical address on a machine is 32 bits. The width of the Tag field in a 64 KB, N-way set associative cache is 20 bits. The N value isA cache is set up with a block size of 32 words. There are 64 blocks in cache and set up to be 4-way set associative. You have byte address 0x8923. Show the word address, block address, tag, and index Show each access being filled in with a note of hit or miss. You are given word address and the access are: 0xff, 0x08, 0x22, 0x00, 0x39, 0xF3, 0x07, 0xc0.
- The sie of the plysical address space of a procesor is 2 bytes. Tue word length is 2 byles Thc capacity of cache memory is 2 bytes The size of cach cache block is 2 words Fur a Kway set-associative cache the length (an number of brts) of the meury tag fields isSuppose a computer using set associative cache has 216 words of main memory and a cache of 128 blocks, and each cache block contains 8 words. If this cache is 2-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields?The width of the physical address on a machine is 30 bits. The width of the tag field in a 64 KB, 16 way block set Associative cache memory is bits.
- For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. a. What is the cache block size in words? b. How many entries does the cache have? Tag 31-13 Index 12-6 Offset 5-0A 64 KB 2-way set-associative cache is byte-addressable and contains 32 byte lines. Memory addresses are 64-bit wide.How wide are the tags in this cache?A cache is set up with a block size of 128 words. There are 32 blocks in cache and set up to be 4-way set associative. You have word address 0x3f42. Show the word address, block address, tag, and set.
- A computer has a 256 KB, K-way set associative write-back data cache with block size of 32 B. The address sent to the cache controller by the processor is of 32 bits. In addition to the address tag, each cache tag directory contains 2 valid bits and 1 modified bit. If 16 bits are used to address tag. What is the minimum value of K?The table below shows a 2-way set associative cache. What is the maximum size of the memory in Kbytes? First Way byte offset (binary) 01 Second Way byte offset (binary) Tag (binary) | (8 bits) Index Tag |(8 bits) | Valid Valid 00 10 11 00 01 10 11 000 AF 1 ВС 86 42 19 6D 1 7F B3 74 83 001 25 3B 69 FD 62 3B 1 D2 6C 68 DC 010 DO 1 44 53 23 62 C3 45 38 87 DA 011 15 1 83 13 48 AB 9B 1 41 8E 90 7A 100 DD 1 36 F4 ЕС ЕВ C5 1 7B ЕВ 41 69 101 4A 72 5B EA 8A 1A 34 3B 54 8E 110 8C 1 11 B1 C8 2E 4B 56 52 5B 27 11 55 A6 61 33 4B FO 48 СА А4 2E О а. 16 O b. 64 О с. 32 O d. 10 O e. 4 O f. 1 O g. 2 O h. 8 Clear my choiceFor a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. We assume that each word has 4 bytes. How many entries does the cache have? Tag Index Offset Block offset | Byte offset 31–12 11-6 5-2 1-0