Calculate C.I, Sample Skewness and Sample Kurtosis from the following grouped data: Class 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-100 Frequency 2 4 3
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- The number of planes to arrive at the Dubai International Airport over N days were recorded and inputted into MINITAB for analysis. Exhibit 1 was subsequently generated. Exhibit 1 Stem-and-Leaf Display: No. of Arrival Leaf Unit = 1 N =* 5 2 01123 10 2 56899 3 0001123 ** (***) 3 6666678888 12 4 01134 57789 00 7 4 2 Calculate he missing values *, ** and *** ii. i. Find the value of the a) Median b) Highest value c) Mode c) Using the stem and leaf diagram in Exhibit 1, Form a frequency table by identifying the class intervals implicitly. Using the table created in 2ci) above, Calculate the sample mean iii. Calculate the sample variance ii.The number of planes to arrive at the Dubai International Airport over N days were recorded and inputted into MINITAB for analysis. Exhibit 1 was subsequently generated. Exhibit 1Stem-and-Leaf Display: No. of Arrival Leaf Unit = 1 N =* 5 2 0112310 2 56899** 3 0001123(***) 3 666667888812 4 011347 4 577892 5 00 Calculate the missing values *, ** and *** ii. Find the value of thea) Median b) Highest value c) Mode c) Using the stem and leaf diagram in Exhibit 1,i. Form a frequency table by identifying the class intervals implicitly. Using the table created in 2ci) above, ii. Calculate the sample mean iii. Calculate the sample varianceThe data given below are measurements (in micrometer units) of the thorax length of the aphid, Pemphigus populitransversus. The aphids were collected in 6 galls on the cottonwood, Populus deltoides. Four alate (winged) aphids were randomly selected from each gall and measured. The alate aphids of each gall are mostly isogenic (identical twins), being decended parthenogenetically from one stem mother. Thus, any variance within galls should be due to environment only. Variance among different galls may be due to differences in genotype and also to environmental differences among galls. Do a one-way ANOVA to test whether there significant intergall variance. Gall No. Replicate No. 1 2 3 4 5 6 1 4.4 5.7 6.2 5.1 6.1 6.2 2 4.9 5.1 5.1 6 6 6.2 3 4.7 5.8 6.1 5.8 5.7 5.3 4 4.8 5.5 5.3 5.9 6 6.3 Average 4.70 5.53 5.68 5.70 5.95 6.00 Ho: Ha: T stat: df: P: Conclusion relative to hypothesis
- The data given below are measurements (in micrometer units) of the thorax length of the aphid, Pemphigus populitransversus. The aphids were collected in 6 galls on the cottonwood, Populus deltoides. Four alate (winged) aphids were randomly selected from each gall and measured. The alate aphids of each gall are mostly isogenic (identical twins), being decended parthenogenetically from one stem mother. Thus, any variance within galls should be due to environment only. Variance among different galls may be due to differences in genotype and also to environmental differences among galls. Do a one-way ANOVA to test whether there significant intergall variance. Gall No. Replicate No. 1 2 3 4 5 6 1 4.4 5.7 6.2 5.1 6.1 6.2 2 4.9 5.1 5.1 6 6 6.2 3 4.7 5.8 6.1 5.8 5.7 5.3 4 4.8 5.5 5.3 5.9 6 6.3 Average 4.70 5.53 5.68 5.70 5.95 6.00 I am having a hard time wording my Ho and Ha, as well as finding ts, df, and P. How do I do this using excel?The number of planes to arrive at the Dubai International Airport over N days were recorded and inputted into MINITAB for analysis. Exhibit 1 was subsequently generated.Exhibit 1Stem-and-Leaf Display: No. of ArrivalLeaf Unit = 1 N =*5 2 0112310 2 56899** 3 0001123(***) 3 666667888812 4 011347 4 577892 5 00i. Calculate he missing values *, ** and *** [3]ii. Find the value of thea) Median [1]b) Highest value [1]c) ModeThe number of planes to arrive at the Dubai International Airport over N days were recorded and inputted into MINITAB for analysis. Exhibit 1 was subsequently generated. Exhibit 1 Stem-and-Leaf Display: No. of Arrival Leaf Unit = 1 N =* 5 2 01123 10 2 56899 ** 3 0001123 (***) 3 6666678888 12 4 01134 7 4 57789 2 5 00 Find the value of the Mode
- The number of planes to arrive at the Dubai International Airport over N days were recorded and inputted into MINITAB for analysis. Exhibit 1 was subsequently generated. Exhibit 1 Stem-and-Leaf Display: No. of Arrival Leaf Unit = 1 N =* 5 2 01123 10 2 56899 ** 3 0001123 (***) 3 6666678888 12 4 01134 7 4 57789 2 5 00 Find the value of the MedianIn a Ni-Cd battery, a fully charged cell is composed of nickelic hydroxide. Nickel is an element that has multiple oxidation states. Assume the following proportions of the states: Nickel Charge Proportions Found 0 0.17 +2 0.33 +3 0.33 +4 0.5-0.33 Determine the variance of the nickel charge. Please enter the answer to 3 decimal places.You sample 1500 dung beetles in a population for 2 alleles A1 and A2 and get the following data: A1A1 825 individuals A1A2 525 individuals A2A2 135 Individuals Is this population in Hardy Weinberg Euilibrium, use a chi square test to determine?
- Determine the kurtosis if the data given is a sample.A farmer has two types of beans and wants to determine which produces a better bean of greater nutritional content. A geneticist was employed to do the investigation examining genotype with nutritional content. The results were as follows: Nutritional Content Genotype High Low bb 8 4 Bb 6 2 Perform a chi square to test the association between genotype and nutritional content. State the null and alternative hypotheses and determine at 95% level of accuracy. Which hypotheses would be accepted?An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow. Analyzer Computerized Electronic Car Compact 52 43 Intermediate 55 44 Full sized 61 45 Use ? = 0.05 to test for any significant differences. State the null and alternative hypotheses. H0: ?Compact ≠ ?Intermediate ≠ ?Full-sizedHa: ?Compact = ?Intermediate = ?Full-sized H0: ?Compact = ?Intermediate = ?Full-sizedHa: ?Compact ≠ ?Intermediate ≠ ?Full-sized H0: ?Computerized = ?Electronic = ?Compact = ?Intermediate = ?Full-sizedHa: Not all the population means are equal. H0: ?Computerized ≠ ?ElectronicHa: ?Computerized = ?Electronic H0: ?Computerized = ?ElectronicHa: ?Computerized ≠ ?Electronic Find the…