Calcula AS para la transformación. = 75.291- C₂(H₂O) = Hielo a 273K' y latm- AH, molk (H₂0) = 33.577- molk vapor a 423K y 1.1atm Datos: k] = 6.0095- ΔΗ mol vap =40.6563- kJ mol
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- Parameters to use for the problems that follow: K = 1.38 × 10-23 J/K q= 1.6 × 10-¹9 coulombs For Silicon at room temperature(T = 300°K): EG = 1.12eV N₁ = = 1 × 10¹0 cm-3 ESi = Ksito (11.8) (8.85 × 10-¹4)F/cm = Hp = 384.62cm²/V - sec, Dp = 10cm²/sec Dn = 32cm²/sec 1230.77cm²/V – sec, flin = Tn = 2.0 × 10-¹sec, Tp = 9.0 x 10-5 sec En = 8.0 × 10-2cm, Ep = 3.0 × 10-²cm 1) A sample of silicon at room temperature and in thermal equilibrium is doped with donor atoms such that ND = 4 x 10¹5 cm-³. Determine the concentration of electrons and holes. NDc. For the reaction 2. CACO,(s) + 2H+ (aq)→ Ca (ag) + H,0(1) + CO, Species S J(mol K) CACO3 (s) 92.9 H* (ag) 0. Ca (aq) -53.1 H20(1) 69.95 CO, (9) 213.7 AS = JKThe following reaction is carried out under standard conditions (25°C and 1 bar): 2CH3OH(1) + 302(g) → 2CO2(g) + 4H₂O(1) AH₁° kJ mol-1 Sᵒ J K-¹ mol-1 C6H12O6 (1) -238.4 212.0 O₂ (g) 0.0 205.1 CO₂(g) -393.5 213.7 H₂O (1) -285.8 69.95 Using the data in the table above: a) Calculate the enthalpy of reaction, ArH, for the reaction: kJ mol-¹ b) Calculate the entropy change, AS, for the reaction: 1 c) Calculate AG for the reaction: kJ mol-¹ d) Is the reaction spontaneous? Put any calculations in here: J mol-1
- Given the data in the table below, AHrxn for the reaction Ca(OH); + 2H;AsO4 → Ca(H;AsO4)2 + 2H;O is _ kJ. [A] -4219 (B] -130.4 [C] -4519 [D] -76.4 AH, (kJ/mol) -986.6|| Substance Ca(ОН), HASO, Ca(H;AsOa)2 -900.4 -2346.0 H;0 -285.9 O A В C DWhat is the concentration of SO42-ions in the solution of silver sulphate with a Kçç value of 1.1x10-5 at 25 ° C?Silver sulphate dissolves in water according to the following reaction.Ag2SO4 (k) ...........> 2 Ag+ (aq) + SO42-(aq) A 1.5 L solution of silver sulfate contains 3 g of dissolved silver sulphate. If extra solid silver sulfate is added to the solution, will it dissolve in the solution? (Ag: 108 g / mol, S: 32 g / mol, O: 16 g / mol)Write the expression for Kc for the following reactions. Ineach case indicate whether the reaction is homogeneousor heterogeneous.(a) 3 NO1g2 ∆ N2O1g2 + NO21g2(b) CH41g2 + 2 H2S1g2 ∆ CS21g2 + 4 H21g2(c) Ni1CO241g2 ∆ Ni1s2 + 4 CO1g2(d) HF1aq2 ∆ H+1aq2 + F-1aq2(e) 2 Ag1s2 + Zn2+1aq2 ∆ 2 Ag+1aq2 + Zn1s2(f) H2O1l2 ∆ H+1aq2 + OH-1aq2(g) 2 H2O1l2 ∆ 2 H+1aq2 + 2 OH-1aq2
- Hospital patients are often given glucose (blood sugar) through a tube connected to a bottle suspended over their beds. Suppose that this "drip" supplies glucose at the rate of 15 mg per minute, and each minute 20% of the accumulated glucose is consumed by the body. Then the amount y(t) of glucose (in excess of the normal level) in the body after t minutes satisfies the following. y' = 15 − 0.2y (Do you see why?) y(0) = 0 (zero excess glucose at t = 0) Solve this differential equation and initial condition.D²1 Quizzes - Spring 2023 SPE XQ Ch 12-14, 18 Public speakin x с app.101edu.co < + 1 Ch 12-14, 18 Public speakin x + Balance the following chemical equation (if necessary): V₂O(s) + HCl(aq) → VOCI (s) + H₂O(1) 2 04- Reset 0 ♡ 2 3 VOCI ( ) 4 D2L Quiz 10-12 - Spring 2023 C X Time's Up! H₂O □ 5 n 0₂ ☐3 04 05 06 л O) 6 + 2+ 7 07 V.O. 2 5 ल = (s) (1) y google - Yahoo Search Rest X ³+ 4+ 8 9 ☐8 • x H₂O 0 (g) (aq) HCI 口。 Delete Aktiv Chemistry G + Update: SubmitTable 5: Calculating AG Temp "C Temp Kelvin Ка In(Ka) AG=-RTIN(Ka) 22. 1 295.25, 0 0044521 -1.12 18950.34962 35 308 .1S 23236.969dH 0- Ocori4 889 -901 45° 318.18°k 0.0016855 - 8.69 22985.918 55° 328.15°K 0.00 0344201 -1.97 21144.06565 Average AG'= AH°= AS= (Note: the slope of the best fit line is equal to -AS" rather than AS" as stated in the video).
- vestion 5 The enthalpy of combustion under a pressure of one atmosphere of one mole of methane at 298K is -212.8 kJ. CH4 (g)+202 (g)>CO2(g) +2H2O(1) a. Calculate the average molecular speed of CO, gas at 298 K (C=12, 0=16) b. Calculate the standard enthalpy of formation of the methane at 298K;AH°(methane(g),298K). Given: AHCH2O(); 298K) = -68.33 kJ/mol); AH(CO2 (g); 298K) = -94.25 kJ/mol) Answer: m/s b) ACH4) %3D kJ/mol A Moving to another question will save this response. rch hp no 96 R U P K alt ctriA Al(s) + 12(s) = All3(s) В CH4(g) + 4CI2(g) = C(4(1) + 4HCI(g) C Fe,O3(s) + 3CO(g) = 2Fe(s) + 3CO2(g) Which of these processes is AH < 0 OB and C only OA and B only O A, B and OC onlyV C Item 14 # Part A 3 Calculate the enthalpy change for the reaction P.Os() +202 (9) P.Om()) given the following enthalpies of reaction P()+30: (9) P.O.(a) AH--1640.1kJ Pa(e)+50₂ (9)→ P400(a) AH-2940.1kJ IVE ΑΣΦΑ AH- Submit Provide Feedback E D Previous Anas Beaut Incorrect; Try Again; 5 attempts remaining $ 4 > R F % 5 T 6 G KJ C Y & 7 H . 00 8
