Hospital patients are often given glucose (blood sugar) through a tube connected to a bottle suspended over their beds. Suppose that this "drip" supplies glucose at the rate of 15 mg per minute, and each minute 20% of the accumulated glucose is consumed by the body. Then the amount y(t) of glucose (in excess of the normal level) in the body after t minutes satisfies the following. y' = 15 − 0.2y (Do you see why?) y(0) = 0 (zero excess glucose at t = 0) Solve this differential equation and initial condition.
Hospital patients are often given glucose (blood sugar) through a tube connected to a bottle suspended over their beds. Suppose that this "drip" supplies glucose at the rate of 15 mg per minute, and each minute 20% of the accumulated glucose is consumed by the body. Then the amount y(t) of glucose (in excess of the normal level) in the body after t minutes satisfies the following. y' = 15 − 0.2y (Do you see why?) y(0) = 0 (zero excess glucose at t = 0) Solve this differential equation and initial condition.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 83QRT: Another step in the metabolism of glucose, which occurs after the formation of glucose6-phosphate,...
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Hospital patients are often given glucose (blood sugar) through a tube connected to a bottle suspended over their beds. Suppose that this "drip" supplies glucose at the rate of 15 mg per minute, and each minute 20% of the accumulated glucose is consumed by the body. Then the amount y(t) of glucose (in excess of the normal level) in the body after t minutes satisfies the following.
| y' | = | 15 − 0.2y (Do you see why?) |
| y(0) | = | 0 (zero excess glucose at t = 0) |
Solve this differential equation and initial condition.
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