Caffeine eine benze, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted to the calibration curve:
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- Sheet 5 From the following data determine the following: Define outlier and then identify the outlier in the data. Determine if the outlier should be kept of discarded from the data. Trial 1 2 3 4 HCl (mL) 22.3 28.4 29.8 29.3 NaOH (mL) 35.2 35.1 34.9 35.0Question 16 Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted to the mark to construct a calibration curve: Caffeine Benzoate Aspartame 1 mL 1 mL 1 mL 2 mL 2 mL 2 mL 3 mL 3 mL 3 mL 4 mL 4 mL 4 mL 5 mL 5 mL 5 mL The 12-oz can mountain dew sample were treated as follows: The 12- oz can were has been left out overnight to get rid the carbonation then, 2 mL were drawn into a plastic syringe, filtered, and placed into a vial. An equal amount of deionized water was added. A 100 μL sample were injected into a sample loop using same parameters with the standards. Assume 12 oz 354.9 mL The following data were obtained: Peak Area Benzoate Caffeine Aspartame Std 1 2.30 3.54 3.33 Std 2 4.10 5.59 5.83 Std 3 7.37 9.98 9.63 Std 4 9.56…Question 17 Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted to the mark to construct a calibration curve: Caffeine Benzoate Aspartame 1 mL 1 mL 1 mL 2 mL 2 mL 2 mL 3 mL 3 mL 3 mL 4 mL 4 mL 4 mL 5 mL 5 mL 5 mL The 12-oz can mountain dew sample were treated as follows: The 12- oz can were has been left out overnight to get rid the carbonation then, 2 mL were drawn into a plastic syringe, filtered, and placed into a vial. An equal amount of deionized water was added. A 100 μL sample were injected into sample loop using same parameters with the standards. Assume 12 oz = 354.9 mL The following data were obtained: Caffeine Peak Area Benzoate 3.54 Aspartame Std 1 2.30 3.33 Std 2 4.10 5.59 5.83 Std 3 7.37 9.98 9.63 Std 4 9.56…
- Question 15 Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted to the mark to construct a calibration curve: Caffeine Benzoate Aspartame 1 mL 1 mL 1 mL 2 mL 2 mL 2 mL 3 mL 3 mL 3 mL 4 mL 4 mL 4 mL 5 mL 5 mL 5 mL The 12-oz can mountain dew sample were treated as follows: The 12- oz can were has been left out overnight to get rid the carbonation then, 2 mL were drawn into a plastic syringe, filtered, and placed into a vial. An equal amount of deionized water was added. A 100 µL sample were injected into a sample loop using same parameters with the standards. Assume 12 oz = 354.9 mL The following data were obtained: Peak Area Benzoate Caffeine Aspartame Std 1 2.30 3.54 3.33 Std 2 4.10 5.59 5.83 Std 3 7.37 9.98 9.63 Std 4 9.56…Question 14 Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted the mark to construct a calibration curve: Caffeine Benzoate Aspartame 1 mL 1 mL 1 mL 2 mL 2 mL 2 mL 3 mL 3 mL 3 mL 4 mL 4 mL 4 mL 5 mL 5 mL 5 mL The 12-oz can mountain dew sample were treated as follows: The 12- oz can were has been left out overnight to get rid the carbonation then, 2 mL were drawn into a plastic syringe, filtered, and placed into a vial. An equal amount of deionized water was added. A 100 μL sample were injected into a sample loop using same parameters with the standards. Assume 12 oz = 354.9 mL The following data were obtained: Caffeine Peak Area Benzoate 3.54 Aspartame Std 1 2.30 3.33 Std 2 4.10 5.59 5.83 Std 3 7.37 9.98 9.63 Std 4 9.56…Question 12 Caffeine, benzoate, and aspartame content of mountain dew soda was determined using reverse phase HPLC. The concentration of the standard used are as follows, caffeine: 0.70 mg/mL, benzoate: 1.6 mg/mL, and aspartame 5.0 mg/mL. The following volume of the standards were taken to a 50.0 mL volumetric flask and diluted to the mark to construct a calibration curve: Caffeine Benzoate Aspartame 1 mL 1 mL 1 mL 2 mL 2 mL 2 mL 3 mL 3 mL 3 mL 4 mL 4 mL 4 mL 5 mL 5 mL 5 mL The 12-oz can mountain dew sample were treated as follows: The 12- oz can were has been left out overnight to get rid the carbonation then, 2 mL were drawn into a plastic syringe, filtered, and placed into a vial. An equal amount of deionized water was added. A 100 μL sample were injected into a sample loop using same parameters with the standards. Assume 12 oz = 354.9 mL The following data were obtained: Peak Area Benzoate Caffeine Aspartame Std 1 2.30 3.54 3.33 Std 2 4.10 5.59 5.83 Std 3 7.37 9.98 9.63 Std 4 9.56…
- 3:36 1 ull LTE O Send a chat What is the number of moles of glucose (C,H,206) in 0.500 of a 0.40 M solution? STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 36.04 0.020 1 0.40 0.20 1.3 180.18 0.500 6.022 x 1023 * Reflect in ePortfolio22:12 Question 23 of 30 Submit How many grams of a solution that is 5.2 % sucrose by mass are needed to obtain 18 g of sucrose X STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 18 100 g solution 3.5 6.022 x 1023 %m sucrose 0.052 5.2 g sucrose 94 350 0.0094 0.94 1 Tap here or pull up for additional resourcesShould be 3 answers in total. Will thumbs up! Next the student conducts two different runs: In RUN 1, 10.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 80.0 mL of wate In RUN 2, 20.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 70.0 mL of wate The following plots were obtained for each of the runs: [crystal orange] vs time (RUN 1) In[crystal orange] vs time (RUN 1) 0.0012 0.001 -2 y--0.4463x- 7.3334 y =-0.0002x + 0.0007 R- 0.6565 R = 0.893 0.0008 4 0.0006 -6 0.0004 -8 0.0002 0.0002 -12 time (hr) time (hr) 1/[crystal orange] vs time (RUN 1) 1/[crystal orange] vs time (RUN 2) 12000 25000 10000 20000 8000 15000 6000 y = 2000x + 1000 R =1 10000 y 4000x + 1000 R =1 4000 2000 5000 time (hr) time (hr) Figure 4. Kinetic traces for the reaction between crystal orange and sodium hydroxide. What is the order with respect to CO? | Select ] What is the order with respect to NaOH? | Select ] What is the value of the averaged rate constant for the reaction above? Give…
- Table 1: Volumes in of iodine in mL used to titrate mixtures of 10 mL of reaction mix and 10 mL of urine. student trial 1 trial 2 trial 3 total volume (mL) a 12.6 11.8 12.5 300 290 b. 10.6 10.7 10.6 11.1 118 12. 10.9 405 13.0 12.5 349 mg vit. C mL iodine TV (mL/hour) 10 mL urine aliquot TVC (mg/hour) =7 (mL) · CF !! What is the hourly vitamin C excretion rate (mg/h) of student b if the CF is 1.06? (include no more than two decimals in your answer, e.g.: 123.45, and do not type the units) 10.6 need ASAP✓ Question Completion Status: Shown below is a calibration curve for the analysis of theobromine and caffeine in chocholate. if an unknown sample has a caffiene peak height of 3.50 cm what is the concentration of caffeine in the sample in ppm? 20 Peak height (centimeters) 15 10 5 0 Theobromine y = 0.1977x-0.2104 25 Unknown Figure 0-7 Gumantative Chemical Analysis, Seventh Edition 2007 Freeman and Company Caffeine y = 0.088 4x-0.030 3 50 Analyte concentration (parts per million) 100 M ED Feb 2 8:3SELECT correct responses only 1) Volume percent (v/v%) is temperature-independent. 2) There are three major approaches to expressing solution concentration in terms of percent concentration: weight percent, volume percent, and weight/volume percent. 3) Weight/volume percent (w/v%) is a unit-less quantity. 4) The term 'percent' refers to 'parts per thousand'. 5)A standard solution is a reagent of known concentration that is used to carry out a volumetric titration. 6) The endpoint of a titration is the theoretical point reached when the amount of added titrant is chemically equivalent to the amount of analyte in a sample. 7) A substance that changes color in response to chemical equivalence is known as an indicator. 8) Given a sufficiently diligent and experienced experimenter, it is sometimes possible to reach a titration volume error value of 0.