An ice cube of mass 1.000kg and temperature −5.00 C is placed in a calorimeter. Then 0.200kg of steam at 100.0 C is added to the calorimeter. When thermal equilibrium is reached, all the ice is melted, and all the steam is condensed, so that only liquid water remains. What is the final equilibrium temperature of the water inside the calorimeter?

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Chapter2: The Kinetic Theory Of Gases
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Problem 89AP: (a) Estimate the specific heat capacity of sodium from the Law of Dulong and Petit. The molar mass...
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An ice cube of mass 1.000kg and temperature −5.00 C
is placed in a calorimeter. Then 0.200kg of steam at
100.0 C is added to the calorimeter. When thermal equilibrium is reached, all the ice is melted, and all the steam is condensed, so that only liquid water remains.
What is the final equilibrium temperature of the water inside the calorimeter? (Look at the
equation sheet for data on water.)

 

Properties of water:
J
Specific Heat (liquid) 4180
kg · K
J
Specific Heat (ice) 2090-
kg · K
J
Heat of Vaporization 2.256×10°
kg
J
Heat of Fusion 3.33×10
kg
+++++++
+++++
++++
Constants:
J
R = 8.31-
J
k =1.38×1023
K
N = 6.03×10²³ mol¯'
mol · K
-27
1 atmosphere = 1.013×10°Pa
u = 1.66×10- kg
Transcribed Image Text:Properties of water: J Specific Heat (liquid) 4180 kg · K J Specific Heat (ice) 2090- kg · K J Heat of Vaporization 2.256×10° kg J Heat of Fusion 3.33×10 kg +++++++ +++++ ++++ Constants: J R = 8.31- J k =1.38×1023 K N = 6.03×10²³ mol¯' mol · K -27 1 atmosphere = 1.013×10°Pa u = 1.66×10- kg
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ISBN:
9781938168161
Author:
OpenStax
Publisher:
OpenStax