Initially you have mwater=4.2kg of water at Twater=66 degrees celcius in a insulated container. You add ice at T ice= -18 degrees celcius to the container and the mix reaches a final, equillibrium temperature of Tf=27 degrees celcius. The specific heat of ice and water are c ice= 2.10×10^3 J/kg×°C) and c water= 4.19×10^3, respectivly, and the latent heat of fusion of water is Lf= 3.34×10^5 J/kg. A.) What is the expression for the mass of ice you added, in terms of the defined quantities? B.) What is the mass of ice, in Kg?
Initially you have mwater=4.2kg of water at Twater=66 degrees celcius in a insulated container. You add ice at T ice= -18 degrees celcius to the container and the mix reaches a final, equillibrium temperature of Tf=27 degrees celcius. The specific heat of ice and water are c ice= 2.10×10^3 J/kg×°C) and c water= 4.19×10^3, respectivly, and the latent heat of fusion of water is Lf= 3.34×10^5 J/kg. A.) What is the expression for the mass of ice you added, in terms of the defined quantities? B.) What is the mass of ice, in Kg?
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter21: Heat And The First Law Of Thermodynamics
Section: Chapter Questions
Problem 71PQ
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Initially you have mwater=4.2kg of water at Twater=66 degrees celcius in a insulated container. You add ice at T ice= -18 degrees celcius to the container and the mix reaches a final, equillibrium temperature of Tf=27 degrees celcius. The specific heat of ice and water are c ice= 2.10×10^3 J/kg×°C) and c water= 4.19×10^3, respectivly, and the latent heat of fusion of water is Lf= 3.34×10^5 J/kg.
A.) What is the expression for the mass of ice you added, in terms of the defined quantities?
B.) What is the mass of ice, in Kg?
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