A W12x79 of AS73 Grade 60 (Fy - 415 MPa) steel is used as a compression member. It is 7.7 m long, fixed at the top and bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows: A = 14,500 mm^2 Ix = 258.6 x 106 mm^4 Iy = 84.375 x 106 mm^4 Calculate the critical slenderness ratio with respect to weak axis buckling using theoretical value of k.
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- A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. a) Determine the allowable tensile strength of the section based on tensile rupture of the net area.b) Determine the allowable tensile strength of the section based on yielding of the gross area.A steel column is pin connected at the top and bottom which is laterally braced and subjected to transverse loading. It carries an axial load of 800 kN and a 70 kN-m moment. Use ASD. The steel section has the following properties: A = 13000 mm² r = 94 mm Ix = 300 x 106 mm4 Sx = 1200 x 103 mm³ L = 3.6 m Yield stress Fy = 248 MPa Axial compressive stress that would be permitted if axial force alone existed, Fa = 115 MPa Compressive bending stress that would be permitted if bending moment alone existed, Fb = 148 MPa Members subjected to both axial compression and bending stresses shall be proportioned to satisfy the following requirements: Mry + 9 Mex Mey Determine the axial compressive stress if axial load only existed. Pr 8 Mrx + Pe 75.82 MPa 61.54 MPa 33.96 MPa 16.25 MPa Determine the bending stress if bending moment alone existed. 76.25 MPa O58.33 MPa 13.33 MPa ≤ 1.0 16.59 MPa Determine the value of both axial and bending moment interaction value, considering the amplification due to…Consider the truss shown in (Egure 1). Suppose that F-60 kN and F₂-25 kN Figure 40 KN Part C Fau 50 AN Submit -2m- D 15m 1of1 > 15m 15m μA Value -F₂ Part A Request Answer Determine the force in member ED of the truss, and state if the member is in tension or compression Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. HA FED Value Submit Part B Request A Determine the force in member EH of the truss, and state if the member is in tension or compression Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. Submit Fon- Value Determine the force in member GH of the truss, and state if the member is in tension or compression. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of…
- 1. A36 steel (Fy=36Ksi, Fu=58Ksi) is used for the tension member shown in the figure below. a. Determine the nominal strength based on the gross area. b. Determine the nominal strength based on the net area. PL % x14 2" 5" 2" 2. The tension member is a PL3/8 × 6 of A242 steel (Fy=50Ksi, Fu=70Ksi). It is connected to a 3/8-in. thick gusset plate, also of A242 steel, with 3/4-inch diameter bolts as shown in the figure below. Determine the nominal block shear strength of the tension member. inDesign the reinforcements of the given T beam below. bf=800mm bw=450mm tf=120mm d=600mm d'=80mm fc'=35MPa fy=350MPa USE NSCP 2015 A.Mu = 1300kN-m, As = B.Mu = 1600kN-m, As = mm2 _mm2, As' = mm2A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. Determine the design tensile strength of the section based on yielding of the gross area. Answer: |0 O O О о
- 6- For a simply supported beam with b=300 mm and d=500 mm, if f = 63MPa, f, = 280 MPa and the net tensile strain is greater than 0.005, then the maximum steel ratio equal............ (a) 0.0406 (b) 0.0310 (c) 0.0287 (d) 0.0180 (e) NonePROBLEM 2: Determine the smallest safe cross-sectional areas, in mm?, of members Cl and CD for the wooden truss shown below. The working stresses are 10 MPa in tension and 8 MPa in compression. (The working stress in compression is reduced due to the danger of buckling.) 8 kN 4 kN 4 kN FINAL ANSWERS 4 kN 4 kN 4 kN - 4 kN Acı mm? K 3.5 m ACD mm2 A в с D E F PA - 6 @ 4 m = 24 mFind the largest permissible value of the load P (lbs) such that the stresses in aluminum and steel must not exceed 20 ksi and 40 ksi, respectively. Also, the total elongation of the compound member is limited to 0.2 inches. 3 ft Aluminum A = 0.6 in.2 E = 10 × 106 psi 4 ft Steel A = 0.4 in.2 E = 29 × 106 psi 2P
- A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. Determine the design tensile strength of the section based on tensile rupture of the net area. Determine the allowable tensile strength of the section based on yielding of the gross area.7 7a 7b 7c Alaterally supported beam was designed for flexure. The beam is safe for shear & deflection. The most economical section is structural tubing however the said section is not readily available at the time of the construction. If you are the engineer in charge of the construction what alternative section will be the best replacement? Why? The section is 8" x 8" x 7.94 mm thick: Use Fy=248 MPa: E=200,000 MPa AISC wall thickness Ix 106 S x 103 Jx 103 mm4 mm3 mm4 rx =ry Area Ag (mm2) mm Designation Weight/m 8x8 7.94 47.36 6,039 79.25 37.84 371.99 60.35 expla'n briefly your cho'ce. (transform your comparative analys's 'nto a narative form to support your cho'ce) 8x8 14.29 80.61 10,258 76.2 59.52 585.02 99.06 8x8 72.7 9,290 76.96 54.53 539.13 90.32 8x8 9.53 56.09 7,161 78.48 44.12 432.62 70.76 mm 12.7 Zx 103 mm3 437.53 714.48 650.57 512.92504.2 Tensile Strength The design tensile strength, $¿Pns and the allowable tensile strength, Pn/N, of tension members, shall be the lower value obtained according to the limit states of tensile yielding in the gross section and tensile rupture in the net section. 1. For tensile yielding in the gross section: Pn = F,A. (504.2-1) P: = 0.90 (LRFD) N, = 1.67 (ASD) 2. For tensile rupture in the net section: Pn = FµAe (504.2-2) Pe = 0.75 (LRFD) h = 2.00 (ASD) %3D %3D An angle bar 100x100x11 mm tension member is connected with 20-mm-diameter bolts as shown in the figure. Both legs of the angles are connected. Use Fy = 248 MPa and Fu = 400 MPa. 6 @ 50 mm 63.5 mm